如何从python列表中抓取名称和删除字符串的其余部分

Question

这是我的名单，其中包含姓名，地址和更多的文字，我只想抓住名字。我怎么能做到这一点。我试过了，但就是找不到。

my_list = ['view profile for\nAli Safaei\nlocated at 1010-650 West Georgia St Vancouver', 'view profile for\nBrian M. Baird\nlocated at 103-1185 West Georgia St Vancouver', 'view profile for\nKarim A. Lalani\nlocated at 1308 Alberni St Vancouver', 'view profile for\nNishant Goswami\nlocated at 201-1743 Robson St Vancouver', 'view profile for\nEric P.J. Bussieres\nlocated at 201-1128 Hornby St Vancouver']

如果你想看到名字，你可以通过

print(my_list[0])
Output
view profile for
Ali Safaei
located at 1010-650 West Georgia St Vancouver

我怎样才能从这个列表中得到那个名字呢？

Answer 1

my_list = ['view profile for\nAli Safaei\nlocated at 1010-650 West Georgia St Vancouver', 'view profile for\nBrian M. Baird\nlocated at 103-1185 West Georgia St Vancouver', 'view profile for\nKarim A. Lalani\nlocated at 1308 Alberni St Vancouver', 'view profile for\nNishant Goswami\nlocated at 201-1743 Robson St Vancouver', 'view profile for\nEric P.J. Bussieres\nlocated at 201-1128 Hornby St Vancouver']
[i.splitlines()[1] for i in my_list]

输出：

['Ali Safaei', 'Brian M. Baird', 'Karim A. Lalani', 'Nishant Goswami', 'Eric P.J. Bussieres']

Answer 2

这将为您提供名称列表：(有关详细信息，请查看Python list comprehension )

names = [entry.splitlines()[1] for entry in my_list]

如果你只需要名字，你可以简单地获取它，如下所示：

firs_name = names[0]

Answer 3

您可以使用此函数获取列表中的所有名称

def name(li):
    def _name(l):
        li_name = l.split('\n')[1]
        return li_name
    return list(map(_name, li))

>>>> name(my_list)
['Ali Safaei', 'Brian M. Baird', 'Karim A. Lalani', 'Nishant Goswami', 'Eric P.J. Bussieres']