对角线Wins的ConnectN检查

Question

因此，我目前正在编写代码来检查connect3游戏中的对角获胜，但是由于某些原因，没有显示打印语句，有人可以检查错误的地方吗

board = [['_','X','X','O'],
         ['_','X','X','O'],
         ['X','X','O','O']]
num_row = 3
num_col = 4
num_piece = 3 #game pieces needed to win 
game_piece = 'X'

# check / diagonal win
for rows in range(num_row - num_piece + 1):
    for cols in range(num_piece, num_col):
        index = 0
        for counts in range(num_piece):
            if board[rows + index][cols - index] == game_piece:
                index += 1
            else:
                break
            if index == num_piece:
                print('game end')

Answer 1

您的代码只测试第一条对角线(从右上角开始)：

>>> for rows in range(num_row - num_piece + 1):
...     for cols in range(num_piece, num_col):
...         index = 0
...         print(f"testing {rows, cols}")
...         for counts in range(num_piece):
...             if board[rows + index][cols - index] == game_piece:
...                 index += 1
...             else:
...                 break
...             if index == num_piece:
...                 print('game end')
...
testing (0, 3)

由于要测试从第2列(第3列)开始的每条对角线，因此需要从该范围的起始处减去1：

>>> for rows in range(num_row - num_piece + 1):
...     for cols in range(num_piece - 1, num_col):
...         index = 0
...         print(f"testing {rows, cols}")
...         for counts in range(num_piece):
...             if board[rows + index][cols - index] == game_piece:
...                 index += 1
...             else:
...                 break
...             if index == num_piece:
...                 print('game end')
...
testing (0, 2)
game end
testing (0, 3)

另请参阅：Finding neighbor cells in a grid with the same value. Ideas how to improve this function?