此代码用于为元素生成单个Map条目。但我希望使用generateInputMapElements从映射中生成随机数量的条目,并将其传递给statusReturnedFromApplyingRule()
@Property
//@Report(Reporting.GENERATED)
boolean statusReturnedFromApplyingRule(@ForAll("generateRule") Rule rule,
@ForAll("generateInputMapElements") Iterable<Map<String, Object>> elements) {
RangeMatchRule rangeMatchRule = new RangeMatchRule();
final RuleIF.Status status = rangeMatchRule.applyRule(rule, elements);
return RuleIF.getEnums().contains(status.toString());
}
@Provide
Arbitrary<Iterable<Map<String, Object>>> generateInputMapElements() {
Arbitrary<Double> metricValueArb = Arbitraries.doubles()
.between(0, 50.0);
Arbitrary<Map<String, Object>> inputMapArb =
metricValueArb.map(metricsValue -> {
Map<String, Object> inputMap = new HashMap<>();
inputMap.put(Utils.METRIC_VALUE, metricsValue);
return inputMap;
});
return inputMapArb.map(inputMap -> {
List<Map<String, Object>> inputMapLst = new ArrayList<>();
inputMapLst.add(inputMap);
return inputMapLst;
});
}How to write a jqwik generator method with nested generators
发布于 2019-10-25 15:36:34
假设您想要一个包含单个条目的map列表(可迭代),我看到了两个基本选项。
选项1-使用Arbitrary.list()生成列表,并直接在生成器代码中指定最小和最大大小:
@Provide
Arbitrary<List<Map<String, Object>>> generateInputMapElements() {
Arbitrary<Double> metricValueArb = Arbitraries.doubles()
.between(0, 50.0);
return metricValueArb
.map(metricsValue -> {
Map<String, Object> inputMap = new HashMap<>();
inputMap.put(Utils.METRIC_VALUE, metricsValue);
return inputMap;
})
.list().ofMinSize(1).ofMaxSize(10);
}选项2-只生成单个映射,并对可迭代对象使用标准注释:
@Property
@Report(Reporting.GENERATED)
boolean statusReturnedFromApplyingRule2(
@ForAll("generateRule") Rule rule,
@ForAll @Size(min = 1, max = 10) Iterable<@From("generateInputMap") Map<String, Object>> elements
) {
...
}
@Provide
Arbitrary<Map<String, Object>> generateInputMap() {
Arbitrary<Double> metricValueArb = Arbitraries.doubles()
.between(0, 50.0);
return metricValueArb
.map(metricsValue -> {
Map<String, Object> inputMap = new HashMap<>();
inputMap.put(Utils.METRIC_VALUE, metricsValue);
return inputMap;
});
}我个人会选择选项2,因为它需要的代码更少。不过是YMMV。
https://stackoverflow.com/questions/58548769
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