如何将JQuery的变量与PHP下拉列表进行匹配

Question

dropdownlist的结果与我想要的数据不匹配。我想知道如何将jquery或javascript变量传递给php，或者这是匹配dropdownlist数据的另一种方式？

    function editbtn(id){

        $('#employee_id_edit').val(id);

        var invoice_id = $('#user-user-list').find("#row_"+id).find("td:eq(1)").text();
        var payment_id = $('#user-user-list').find("#row_"+id).find("td:eq(2)").text();
        var category = $('#user-user-list').find("#row_"+id).find("td:eq(3)").text();
        var sale_person = $('#user-user-list').find("#row_"+id).find("td:eq(4)").text();
        var amount = $('#user-user-list').find("#row_"+id).find("td:eq(5)").text();
  
        $('#invoice_id_edit').val(invoice_id);
        $('#payment_id_edit').val(payment_id);
        $('#product_type_edit').val(category);
        $('#employee_edit').val(sale_person);
        $('#amount_edit').val(amount);  

    }

              <label for="employee">Sale Person</label>
              <select id="employee_edit" name="employee_edit" class="form-control" autocomplete="off">
                        <?php
                        $employee_model = $registry->get('loader')->model('user');
                        $employee = $employee_model->getEmployee();
                        if(null !== $employee) {
                            foreach ($employee as $employee) {
                                ?>
                                <option  value="<?php echo $employee['username'];?>" selected><?php echo $employee['username']; ?></option>
                                <?php
                            }
                        } else {
                            ?>
                            <option>No Employee Available</option>
                            <?php
                        }
                        ?>
              </select>

Answer 1

我认为你应该使用像'jquery select2'(https://select2.org/)这样的jquery插件，或者创建一些自定义的ajax请求来从js发送数据到PHP后端，然后获取并处理来自js部分的响应。