我已经创建了一个方法,但不知道如何传递参数和管理响应参数。
class func postWithURL(serverlink:String, methodname:String, param:NSDictionary, key:String, CompletionHandler : @escaping (Bool,NSDictionary) -> ())谢谢
发布于 2018-07-24 18:13:50
下面是调用方法的方法:
self.postWithURL(serverlink: "link", methodname: "name", param:NSDictionary(), key: "key") { (bool, dictionary) in
// you code goes here
}https://stackoverflow.com/questions/51495951
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