如何检查homebrew-core是否是bash脚本中的浅层克隆？

Question

如何在bash脚本中检查当前homebrew-core和homebrew-cask是否是浅克隆，如果是则取消浅克隆？如果它们已经不浅，我也想打印一条消息。

在已经不浅的克隆上运行git -C "/usr/local/Homebrew/Library/Taps/homebrew/homebrew-cask" fetch --unshallow只会给出一条错误消息，而不是正常的处理。

我试过了

if [[ "git rev-parse --is-shallow-repository /usr/local/Homebrew/Library/Taps/homebrew/homebrew-core" == "false" ]] 
then
    echo "homebrew core is already non shallow. Moving to next step."
else
    git -C "/usr/local/Homebrew/Library/Taps/homebrew/homebrew-core" fetch --unshallow
fi

但是得到了

fatal: --unshallow on a complete repository does not make sense

Answer 1

这似乎起作用了。

if [[ "git rev-parse --is-shallow-repository /usr/local/Homebrew/Library/Taps/homebrew/homebrew-core | grep -q 'false'" ]] 
then
    echo "homebrew core is already non shallow. Moving to next step."
else
    git -C "/usr/local/Homebrew/Library/Taps/homebrew/homebrew-core" fetch --unshallow
fi

Answer 2

您可以使用类似于

$ for d in homebrew-core homebrew-cask
do
    (cd /usr/local/Homebrew/Library/Taps/homebrew/$d && git rev-parse --is-shallow-repository)
done

如果存储库很浅，它将输出true或false。