我试着用"-“来认识集合的不同。例如:
Set a = 1 2 3 4;
Set b = 3 4 5 6;
Set c = a - b; // (1 2);我应该如何重载操作符?我尝试使用frienldy函数,但它不能与变量"size“一起工作。Visual Studio在第28行(size++;)显示错误"c2597“我无法理解,如何重载"-”以便在两个集合中使用它。当我重载类的方法时,我只能使用一个参数。当我使用friend-function时,我可以使用两个参数(Set a,Set b),但我不能使用变量"size“。
#include <iostream>
#include <locale.h>
#include <conio.h>
#include <vector>
using namespace std;
class Set {
private:
int size;
vector <int> vect;
public:
Set() { size = 0; }
~Set() { vect.clear(); }
void Enter();
void Show();
friend Set operator-(Set a, Set b)
{
size = 0;
vect.clear();
int i, j, n = 0;
for (i = 0; i < a.size; i++) {
int cnt = 0;
for (j = 0; j < b.size; j++)
{
if (a.vect[i] == b.vect[j]) cnt++;
}
if (cnt == 0) {
size++;
vect.push_back(a.vect[i]);
}
}
return a;
}
void add()
{
int element;
cout << "Введите новый элемент " << endl;
cin >> element;
size = size + 1;
vect.push_back(element);
}
};
void Set::Enter() {
cout << "Введите размер " << endl;
cin >> size;
vect.resize(size);
cout << "Введите элементы :" << endl;
for (int i = 0; i < size; i++)
{
cin >> vect[i];
}
}
void Set::Show() {
cout << "Множество: " << endl;
for (int i = 0; i < size; i++)
cout << vect[i] << " ";
cout << endl;
}
int main() {
setlocale(LC_ALL, "RUS");
Set a;
a.Enter();
Set b;
b.Enter();
Set c;
c = a - b;
c.Show();
c.add();
c.Show();
_getch();
return 0;
}更新:我是通过方法做到的:
Set operator-(const Set& b)
{
Set a = *this;
Set tmp;
tmp.size = 0;
vect.clear();
int i, j, n = 0;
for (i = 0; i < a.size; i++) {
int cnt = 0;
for (j = 0; j < b.size; j++)
{
if (a.vect[i] == b.vect[j]) cnt++;
}
if (cnt == 0) {
tmp.size++;
tmp.vect.push_back(a.vect[i]);
}
}
return tmp;
}发布于 2020-02-21 21:21:49
friend函数不是成员方法,因此您必须移除/替换(隐式) this作为size = 0的用法,您可以添加额外的对象:
friend Set operator-(Set a, Set b)
{
Set res;
for (int i = 0; i < a.size; i++) {
int cnt = 0;
for (int j = 0; j < b.size; j++)
{
if (a.vect[i] == b.vect[j]) cnt++;
}
if (cnt == 0) {
res.size++;
res.vect.push_back(a.vect[i]);
}
}
return res;
}https://stackoverflow.com/questions/60339387
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