我正在使用Beam SQL,并尝试将整数转换为日期时间字段。
Schema resultSchema =
Schema.builder()
.addInt64Field("detectedCount")
.addStringField("sensor")
.addInt64Field("timestamp")
.build();
PCollection<Row> sensorRawUnboundedTimestampedSubset =
sensorRowUnbounded.apply(
SqlTransform.query(
"select PCOLLECTION.payload.`value`.`count` detectedCount, \n"
+ "PCOLLECTION.payload.`value`.`id` sensor, \n"
+ "PCOLLECTION.`timestamp` `timestamp` \n"
+ "from PCOLLECTION "))
.setRowSchema(resultSchema);对于一些计算和窗口,我想将timestamp转换为Datetime字段?请提供一些将resultSchema中的timestamp转换为DateTime的指针。数据类型。
发布于 2019-07-20 06:16:33
在Beam (or in Calcite)中没有现成的方法可以做到这一点。简短版本-方解石或光束无法知道您实际如何存储整数中的日期或时间戳。然而,假设你有epoch millis,这应该是可行的:
@Test
public void testBlah() throws Exception {
// input schema, has timestamps as epoch millis
Schema schema = Schema.builder().addInt64Field("ts").addStringField("st").build();
DateTime ts1 = new DateTime(2019, 8, 9, 10, 11, 12);
DateTime ts2 = new DateTime(2019, 8, 9, 10, 11, 12);
PCollection<Row> input =
pipeline
.apply(
"createRows",
Create.of(
Row.withSchema(schema).addValues(ts1.getMillis(), "two").build(),
Row.withSchema(schema).addValues(ts2.getMillis(), "twelve").build()))
.setRowSchema(schema);
PCollection<Row> result =
input.apply(
SqlTransform.query(
"SELECT \n"
+ "(TIMESTAMP '1970-01-01 00:00:00' + ts * INTERVAL '0.001' SECOND) as ts, \n"
+ "st \n"
+ "FROM \n"
+ "PCOLLECTION"));
// output schema, has timestamps as DateTime
Schema outSchema = Schema.builder().addDateTimeField("ts").addStringField("st").build();
PAssert.that(result)
.containsInAnyOrder(
Row.withSchema(outSchema).addValues(ts1, "two").build(),
Row.withSchema(outSchema).addValues(ts2, "twelve").build());
pipeline.run();
}或者,你也可以使用java,而不是SQL,只需在SqlTransform的输出中应用一个自定义的ParDo即可。在该ParDo中,从Row对象提取整数时间戳,将其转换为DateTime,然后发出它,例如,作为具有不同模式的另一行的一部分。
https://stackoverflow.com/questions/57117983
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