我有一个Delphi2010应用程序,它导出一个动态链接库并具有library头文件。它在TThread中创建自己的MainForm,如下所示:
var
ActiveThread: TActive;
type
TActive= class(TThread)
protected
procedure Execute; override;
end;
procedure TActive.Execute;
begin
Application.Initialize;
Application.CreateForm(MyForm, form);
Application.Run;
end;
begin
ActiveThread := TActive.Create(true);
ActiveThread.FreeOnTerminate := true;
ActiveThread.Resume;
end.每当我通过LoadLibrary函数加载这个DLL时,应用程序都运行得很好。(显然,它使用我传递给LoadLibrary的线程作为主线程,没有任何问题)
但是,如果我试图通过在Options ->应用程序中更改生成的输出来将此DLL导出为实际的EXE。并将标题从library更改为program,然后构建它并执行输出EXE而不是通过windows api加载DLL,应用程序在尝试创建表单时挂起,特别是在Application.CreateForm(MyForm, form);。如果我从线程中删除应用程序初始化,并将其放在main例程中,它就会运行得很好。
我试图呈现的表单只是一个空表单。有什么想法吗?
发布于 2021-02-18 07:28:21
当将这段代码编译为program时,它将在运行时尝试在到达end.时自行终止,甚至在工作线程有机会运行之前,这可能(也很可能)发生在Application对象被销毁之后。在让程序退出之前,您必须等待工作线程完成其工作,例如:
program MyProgram;
uses
Classes, Forms, MyForm;
type
TActive = class(TThread)
protected
procedure Execute; override;
end;
procedure TActive.Execute;
begin
Application.Initialize;
Application.CreateForm(TMyForm, MyForm);
Application.Run;
end;
var
ActiveThread: TActive;
begin
ActiveThread := TActive.Create(False);
ActiveThread.WaitFor;
ActiveThread.Free;
end.但是,真的没有充分的理由使用这样的工作线程,这违背了使用线程的全部目的,所以你最好干脆干脆把它去掉:
program MyProgram;
uses
Forms, MyForm;
begin
Application.Initialize;
Application.CreateForm(TMyForm, MyForm);
Application.Run;
end.另一方面,如果您试图在program和library项目之间共享公共代码,那么您可以将Application代码包装在函数中,并让项目决定哪个线程调用该函数,例如:
unit MyApp;
interface
procedure RunMyApp;
implementation
uses
Forms, MyForm;
procedure RunMyApp;
begin
Application.Initialize;
Application.CreateForm(TMyForm, MyForm);
Application.Run;
end;
end.program MyProgram;
uses
MyApp;
begin
RunMyApp;
end.library MyLibrary
uses
Classes, MyApp;
type
TActive = class(TThread)
protected
procedure Execute; override;
end;
procedure TActive.Execute;
begin
RunMyApp;
end;
var
ActiveThread: TActive;
begin
ActiveThread := TActive.Create(True);
ActiveThread.FreeOnTerminate := True;
ActiveThread.Resume;
end.https://stackoverflow.com/questions/66251082
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