给定一个命名的字符向量列表，输出一个新列表，其中所有字符向量的唯一元素与原始列表的名称颠倒放置

Question

这是一个简化的例子。我的真实数据集非常大，所以答案在计算上应该是便宜的。

start.list <- list(cb_1 = c("VR_1", "VR_2", "VR_3"), cb_2 = c("VR_2", "VR_3", "VR_4"), 
cb_3 = c("VR_3", "VR_4", "VR_5"))

> start.list  
$cb_1  
[1] "VR_1" "VR_2" "VR_3"

$cb_2  
[1] "VR_2" "VR_3" "VR_4"

$cb_3  
[1] "VR_3" "VR_4" "VR_5"

所需输出列表：

> output.list  
$VR_1  
[1] "cb_1"

$VR_2  
[1] "cb_1" "cb_2"

$VR_3  
[1] "cb_1" "cb_2" "cb_3"

$VR_4  
[1] "cb_2" "cb_3"

$VR_5  
[1] "cb_3"

Answer 1

使用enframe和unnest -

tibble::enframe(start.list) %>%
  tidyr::unnest(value) %>%
  {split(.$name, .$value)}

#$VR_1
#[1] "cb_1"

#$VR_2
#[1] "cb_1" "cb_2"

#$VR_3
#[1] "cb_1" "cb_2" "cb_3"

#$VR_4
#[1] "cb_2" "cb_3"

#$VR_5
#[1] "cb_3"