查找python中的文本中是否存在单词的逻辑

Question

我有一个字符串和一个单词列表，我想检查它们是否存在于给定的文本字符串中。我正在使用下面的logic.....is来优化它：

import re
text="""
Python is an interpreted, object-oriented, high-level programming language with dynamic semantics.
Its high-level built in data structures, combined with dynamic typing and dynamic binding, make
it very attractive for Rapid Application Development"""
tokens_text=re.split(" ",text)
list_words=["programming","Application"]
if (len(set(list_words).intersection(set(tokens_text)))==len(list_words)):
    print("Match_Found")

Answer 1

使用set.issubset(other)操作：

text="""
Python is an interpreted, object-oriented, high-level programming language with dynamic semantics.
Its high-level built in data structures, combined with dynamic typing and dynamic binding, make
it very attractive for Rapid Application Development"""
tokens = text.split()
list_words = ["programming", "Application"]

if (set(list_words).issubset(set(tokens))):
    print("Match_Found")

或者简单地使用all函数：

if all(x in tokens for x in list_words):
    print("Match_Found")

Answer 2

你可以使用python的in运算符，我不知道它是不是更快。

str = "Messi is the best soccer player"

"soccer" in str
-> True

"football" in str
-> False