如何在powershell中转义大括号

Question

我有这个

$content = "loose text{{comments}} = {{yolo}}{{comments}} = {{yolo2}}{{comment}} = {{yolo3}}{{comment}} = {{yolo4}}loose text2";

我想摆脱这些括号。我在某处读到，为了逃避它，你将它们加倍，但即使这样，它也不起作用。

我得到了

Cannot convert value "loose text{{comments}} = {{yolo}}{{comments}} = {{yolo2}}{{comment}} = {{yolo3}}{{comment}} = {{yolo4}}loose text2" to type "System.Xml.XmlDocument". Error: "The specified node cannot be inserted as the valid child of this node, 
because the specified node is the wrong type."
At line:1 char:1
+ $content = "loose text{{comments}} = {{yolo}}{{comments}} = {{yolo2}}{{comment}} ...
+ ~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
    + CategoryInfo          : MetadataError: (:) [], ParentContainsErrorRecordException
    + FullyQualifiedErrorId : RuntimeException

Answer 1

PS中的转义字符是"back-tic“= `。但是，在所给出的代码中，字符串中只包含{}应该不会有任何问题。

在任何需要转义它的情况下，只需使用下面的示例：

$content = "loose text`{comments`} = `{yolo`}`{comments`} = `{yolo2`}`{comment`} = `{yolo3`}`{comment`} = `{yolo4`}loose text2"