用c#读取Yamldotnet

Question

当我尝试使用c#读取Yaml文件时遇到一些问题，需要帮助才能完成此任务，我如何才能将这样的Yaml文件读入变量以便处理它们。

FileConfig: 
  sourceFolder: /home
  destinationFolder: /home/billy/my-test-case
  scenarios: 
  - name: first-scenario 
    alterations: 
    - tableExtension: ln
      alterations: 
      - type: copy-line
        sourceLineIndex: 0
        destinationLineIndex: 0
      - type: cell-change
        sourceLineIndex: 0
        columnName: FAKE_COL
        newValue: NEW_Value1
    - tableExtension: env
      alterations: 
      - type: cell-change
        sourceLineIndex: 0
        columnName: ID
        newValue: 10

以下是我的代码

string text = System.IO.File.ReadAllText(@"test.yaml");

var deserializer = new Deserializer();
var result = deserializer.Deserialize<List<Hashtable>>(new StringReader(text));
/*foreach (var item in result)
{
    Console.WriteLine("Item:");
    Console.WriteLine(item.GetType());
    foreach (DictionaryEntry entry in item)
    {
        Console.WriteLine("- {0} = {1}", entry.Key, entry.Value);
    }
}    */

Answer 1

最简单的方法是创建文档的C#模型。然后，您就可以使用Deserializer用文档中显示的数据填充该模型。文档的一种可能模型是：

public class MyModel
{
    [YamlMember(Alias = "FileConfig", ApplyNamingConventions = false)]
    public FileConfig FileConfig { get; set; }
}

public class FileConfig
{
    public string SourceFolder { get; set; }
    public string DestinationFolder { get; set; }
    public List<Scenario> Scenarios { get; set; }
}

public class Scenario
{
    public string Name { get; set; }
    public List<Alteration> Alterations { get; set; }
}

public class Alteration
{
    public string TableExtension { get; set; }
    public List<TableAlteration> Alterations { get; set; }  
}

public class TableAlteration
{
    public string Type { get; set; }
    public int SourceLineIndex { get; set; }
    public int DestinationLineIndex { get; set; }
    public string ColumnName { get; set; }
    public string NewValue { get; set; }
}

您可以反序列化到该模型，如下所示：

var deserializer = new DeserializerBuilder()
    .WithNamingConvention(CamelCaseNamingConvention.Instance)
    .Build();

var obj = deserializer.Deserialize<MyModel>(yaml);

您可以在此处运行以下代码：https://dotnetfiddle.net/SRABFM

当然，我在这里建议的模型是非常幼稚的，并且对您的领域模型有更多的了解，您肯定能够提出更好的模型。