“'typeof”：原型，空

Question

我在返回一个订阅对象时遇到了下面的错误。

错误：-类型'Subscription‘缺少类型'typeof Subscription’的以下属性: prototype，空

我的代码是：

import { ActivatedRoute, Params } from '@angular/router';
import { Subscription } from 'rxjs/Subscription';
import { Component, OnInit, OnDestroy } from '@angular/core';

@Component({
  selector: 'app-user',
  templateUrl: './user.component.html',
  styleUrls: ['./user.component.css']
})
export class UserComponent implements OnInit, OnDestroy {
  user :{id:number, name:string};

  private paramSubscription = Subscription;

  constructor(private route:ActivatedRoute) { }

  ngOnInit(): void {
    this.user={
    id: this.route.snapshot.params['id'],
    name: this.route.snapshot.params['name']
    };
     this.paramSubscription = this.route.params.
     subscribe(
       (params:Params) => {
         this.user.id=params['id'],
         this.user.name=params['name']
       }
     );
  }

  ngOnDestroy(){
    this.paramSubscription.unsubscribe();
  }

}

Answer 1

嗨，伙计们，我弄错了，这只是我的订阅声明。代码应该是这样的.

import { ActivatedRoute, Params } from '@angular/router';
import { Subscription } from 'rxjs/Subscription';
import { Component, OnInit, OnDestroy } from '@angular/core';

@Component({
  selector: 'app-user',
  templateUrl: './user.component.html',
  styleUrls: ['./user.component.css']
})
export class UserComponent implements OnInit, OnDestroy {
  user :{id:number, name:string};

  private paramSubscription:Subscription;

  constructor(private route:ActivatedRoute) { }

  ngOnInit(): void {
    this.user={
    id: this.route.snapshot.params['id'],
    name: this.route.snapshot.params['name']
    };
     this.paramSubscription = this.route.params.
     subscribe(
       (params:Params) => {
         this.user.id=params['id'],
         this.user.name=params['name']
       }
     );
  }

  ngOnDestroy(){
    this.paramSubscription.unsubscribe();
  }

}