DJGPP让DOS‘多目标模式’

Question

我正在使用DOS下的DJGPP make。

这是我的主要Makefile：

BIN_DIR = bin
OBJ_DIR = obj
DIRS_FOR_CREATION = $(BIN_DIR) $(OBJ_DIR)
SOURCE_DIRS = argparse logger transmission tests

EXECUTABLE_NAME = $(notdir $(shell pwd))
EXECUTABLE_FILE = $(BIN_DIR)/$(EXECUTABLE_NAME)

CC = cc

CFLAGS =
INCLUDES =
LFLAGS =
LIBS =

MAIN_SOURCE = main.c
MAIN_OBJ = $(OBJ_DIR)/main.o

all: directories submodules main $(EXECUTABLE_FILE)
    @echo $(EXECUTABLE_NAME) was compiled

directories:
    mkdir -p $(DIRS_FOR_CREATION)

submodules: 
    $(MAKE) -C $(word 1, $(SOURCE_DIRS))
    $(MAKE) -C $(word 2, $(SOURCE_DIRS))
    $(MAKE) -C $(word 3, $(SOURCE_DIRS))
    $(MAKE) -C $(word 4, $(SOURCE_DIRS))

main:
    $(CC) $(CFLAGS) $(INCLUDES) -c $(MAIN_SOURCE) -o $(MAIN_OBJ)

$(EXECUTABLE_FILE): $(MAIN_SOURCE)
    $(CC) $(CFLAGS) $(INCLUDES) -o $(EXECUTABLE_FILE) $(MAIN_OBJ) $(LFLAGS) $(LIBS)

这在QNX上运行得很好，但在DOSBox中我得到了以下错误：

makefile:19: *** multiple target patterns. Stop.

19行是all: directories submodules main $(EXECUTABLE_FILE)。我应该怎么做才能解决这个问题？

Answer 1

您应该添加：

$(info EXECUTABLE_NAME = '$(EXECUTABLE_NAME)')
$(info EXECUTABLE_FILE = '$(EXECUTABLE_FILE)')

所以你可以看到这个变量包含了什么。我怀疑它包含一个冒号(:)，这是特别要制作的。