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创建GraphQLHttpClient时出现GraphQLClient错误: IGraphQLWebsocketJsonSerializer
EN

Stack Overflow用户
提问于 2020-03-03 00:02:33
回答 1查看 3.5K关注 0票数 2

使用GraphQL版本2.1.0,我不能创建对象: GraphQLHttpClient。

我立即得到以下错误:

代码语言:javascript
复制
System.AggregateException
  HResult=0x80131500
  Message=One or more errors occurred. (no implementation of "GraphQL.Client.Abstractions.Websocket.IGraphQLWebsocketJsonSerializer" found)
  Source=System.Private.CoreLib
  StackTrace:
   at System.Threading.Tasks.Task.ThrowIfExceptional(Boolean includeTaskCanceledExceptions)
   at System.Threading.Tasks.Task.Wait(Int32 millisecondsTimeout, CancellationToken cancellationToken)
   at System.Threading.Tasks.Task.Wait()
   at (...)Program.Main(String[] args) in (..)\Program.cs:line 22

  This exception was originally thrown at this call stack:
    GraphQL.Client.Abstractions.GraphQLJsonSerializerExtensions.EnsureAssigned<TSerializerInterface>(TSerializerInterface)
    GraphQL.Client.Http.GraphQLHttpClient.GraphQLHttpClient(GraphQL.Client.Http.GraphQLHttpClientOptions, System.Net.Http.HttpClient)
    GraphQL.Client.Http.GraphQLHttpClient.GraphQLHttpClient(GraphQL.Client.Http.GraphQLHttpClientOptions)
    GraphQL.Client.Http.GraphQLHttpClient.GraphQLHttpClient(System.Action<GraphQL.Client.Http.GraphQLHttpClientOptions>)
    GraphQL.Client.Http.GraphQLHttpClient.GraphQLHttpClient(System.Uri)
    GraphQL.Client.Http.GraphQLHttpClient.GraphQLHttpClient(string)
    (...)Program.MainAsync() in Program.cs

Inner Exception 1:
InvalidOperationException: no implementation of "GraphQL.Client.Abstractions.Websocket.IGraphQLWebsocketJsonSerializer" found

代码:

代码语言:javascript
复制
using Newtonsoft.Json;
using Newtonsoft.Json.Linq;
using System;
using System.IO;
using System.Net;
using System.Text;
using GraphQL;
using GraphQL.Client;
using System.Threading.Tasks;
using System.Collections.Generic;
using GraphQL.Client.Abstractions;
using GraphQL.Client.Http;

namespace OW_1
{
    class Program
    {

        static void Main(string[] args)
        {
            MainAsync().Wait();
        }

        static async Task MainAsync()
        {
            var graphQLClient = new GraphQLHttpClient("X");

        }
    }
}

它在与GraphQLHttpClient的线路上崩溃。以前,我使用过1.0.3 (带有: GraphQLClient类),并且它起作用了。

EN

回答 1

Stack Overflow用户

发布于 2020-06-10 02:33:08

所以,如果人们找到了这个问题,知道什么最终会起作用:

代码语言:javascript
复制
        var graphQLOptions = new GraphQLHttpClientOptions
        {
            EndPoint = new Uri("https://your_endpoint.com/output", UriKind.Absolute),
        };
       var graphQLClient = new GraphQLHttpClient(graphQLOptions, new NewtonsoftJsonSerializer());

       var msg = new GraphQLRequest
        {
            Query = "query { yourSampleQuery { yourData} }"
        };
       var graphQLResponse = await graphQLClient.SendQueryAsync<dynamic>(msg).ConfigureAwait(false);

只需要考虑的一点是var graphQLClient应该是静态的,所以我们不会在每次调用时更新它。

票数 1
EN
页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/60492576

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