使用其他数组对对象数组进行排序

Question

我创建了这个对象数组：

const palette = [
  {
    color: 'Blue',
    brightness: 'Soft',
  },
  {
    color: 'Blue',
    brightness: 'Medium',
  },
  {
    color: 'Blue',
    brightness: 'Principal',
  },
  {
    color: 'Magenta',
    brightness: 'Soft',
  },
  {
    color: 'Magenta',
    brightness: 'Medium',
  },
  {
    color: 'Magenta',
    brightness: 'Principal',
  }
]

我想要一个新的数组，其中对象的顺序如下：

const colorOrder = ['Blue', 'Magenta']
const brightnessOrder = ['Principal', 'Soft', 'Medium']

所以这就是我想要的结果：

const colors = [
  {
    color: 'Blue',
    brightness: 'Principal',
  },
  {
    color: 'Blue',
    brightness: 'Soft',
  },
  {
    color: 'Blue',
    brightness: 'Medium',
  },
  {
    color: 'Magenta',
    brightness: 'Principal',
  }
  {
    color: 'Magenta',
    brightness: 'Soft',
  },
  {
    color: 'Magenta',
    brightness: 'Medium',
  },
]

我尝试这个函数：

function sortArrayByAnotherArray(array: any[], order: number[] | string[], key: string) {
  const newArray = array.slice(0).sort((a, b) => {
    const A = a[key]
    const B = b[key]
    return order.indexOf(A) < order.indexOf(B) ? 1 : -1
  })
  return newArray
}

我这样称呼它：

const palette1 = sortArrayByAnotherArray(
  palette,
  brightnessOrder,
  'brightness'
)
const palette2 = sortArrayByAnotherArray(
  palette1,
  colorOrder,
  'color'
)

console.log('\n', palette)

console.log('\n', brightnessOrder)
console.log(palette1)

console.log('\n', colorOrder)
console.log(palette2)

结果是：

`
` [ { color: 'Blue', brightness: 'Soft' },
  { color: 'Blue', brightness: 'Medium' },
  { color: 'Blue', brightness: 'Principal' },
  { color: 'Magenta', brightness: 'Soft' },
  { color: 'Magenta', brightness: 'Medium' },
  { color: 'Magenta', brightness: 'Principal' } ]
`
` [ 'Principal', 'Soft', 'Medium' ]
[ { color: 'Blue', brightness: 'Medium' },
  { color: 'Magenta', brightness: 'Medium' },
  { color: 'Blue', brightness: 'Soft' },
  { color: 'Magenta', brightness: 'Soft' },
  { color: 'Blue', brightness: 'Principal' },
  { color: 'Magenta', brightness: 'Principal' } ]
`
` [ 'Blue', 'Magenta' ]
[ { color: 'Magenta', brightness: 'Medium' },
  { color: 'Magenta', brightness: 'Soft' },
  { color: 'Magenta', brightness: 'Principal' },
  { color: 'Blue', brightness: 'Medium' },
  { color: 'Blue', brightness: 'Soft' },
  { color: 'Blue', brightness: 'Principal' } ]

这是混乱的，顺序不像数组中的顺序:颜色是反转的，也是亮度值。那么我认为调用这个函数两次(或更多)会产生问题。有没有办法解决这个问题？有一种聪明的方式来做我需要的事吗？

Answer 1

您可以使用logical OR ||和索引的增量链接所需的订单。

​

const
    palette = [{ color: 'Blue', brightness: 'Soft' }, { color: 'Blue', brightness: 'Medium' }, { color: 'Blue', brightness: 'Principal' }, { color: 'Magenta', brightness: 'Soft' }, { color: 'Magenta', brightness: 'Medium' }, { color: 'Magenta', brightness: 'Principal' }],
    colorOrder = ['Blue', 'Magenta'],
    brightnessOrder = ['Principal', 'Soft', 'Medium'];

palette.sort((a, b) => 
    colorOrder.indexOf(a.color) - colorOrder.indexOf(b.color) ||
    brightnessOrder.indexOf(a.brightness) - brightnessOrder.indexOf(b.brightness)
);

console.log(palette);

.as-console-wrapper { max-height: 100% !important; top: 0; }

​

一种使用函数和给定的顺序数组对副本进行排序的方法。

​

function sortArrayByAnotherArrays(data, orders) {
    const
        getObject = array => array.reduce((r, k, i) => (r[k] = i + 1, r), {}),
        objects = orders.map(([k, a]) => [k, getObject(a)]);

    return data
        .slice()
        .sort((a, b) => {
            var v;
            objects.some(([k, o]) => v = o[a[k]] - o[b[k]]);
            return v;
        });
}

const
    palette = [{ color: 'Blue', brightness: 'Soft' }, { color: 'Blue', brightness: 'Medium' }, { color: 'Blue', brightness: 'Principal' }, { color: 'Magenta', brightness: 'Soft' }, { color: 'Magenta', brightness: 'Medium' }, { color: 'Magenta', brightness: 'Principal' }],
    colorOrder = ['Blue', 'Magenta'],
    brightnessOrder = ['Principal', 'Soft', 'Medium'],
    ordered = sortArrayByAnotherArrays(
        palette,
        [
            ['color', colorOrder],           // [key, values in order]
            ['brightness', brightnessOrder]
        ]
    );

console.log(ordered);

.as-console-wrapper { max-height: 100% !important; top: 0; }

​

Answer 2

如果结果是反转的，则可以尝试反转排序条件

return order.indexOf(A) > order.indexOf(B) ? 1 : -1

Answer 3

按colorOrder中每个对象的颜色索引的差异排序，并与brightnessOrder中每个对象的亮度索引的差异交替排序。

请记住，.sort会就地排序-- sorted与palette是同一个对象。如果您不想改变原始数组，请先克隆它。

​

const palette=[{color:"Blue",brightness:"Soft"},{color:"Blue",brightness:"Medium"},{color:"Blue",brightness:"Principal"},{color:"Magenta",brightness:"Soft"},{color:"Magenta",brightness:"Medium"},{color:"Magenta",brightness:"Principal"}];

const colorOrder = ['Blue', 'Magenta'];
const brightnessOrder = ['Principal', 'Soft', 'Medium'];

const sorted = palette.sort((a, b) => (
  colorOrder.indexOf(a.color) - colorOrder.indexOf(b.color) ||
  brightnessOrder.indexOf(a.brightness) - brightnessOrder.indexOf(a.brightness)
));
console.log(sorted);

​