我希望从数组值创建链接的目的是链接将显示详细信息的模式。
所以我有这个数组:
array:1 [▼
42 => "00285",
43 =? "00123"
]我找到了一些类似这样的方法:
foreach ($certificate->pluck('number', 'id')->toArray() as $href => $text) {
if ($href != $text) {
echo '<a href="?page=' . $href . '">' . $text . '</a>, ';
} else {
echo $text;
}
}但在某些情况下,我的控制器将中断到下一个网格“回显”必须是“返回”,
我想要的示例网格:

但上面的代码如下所示:

在第一张图片中不显示网格内部的值
编辑:
我的代码来自图片1- laravel-admin
$grid->column('Sertifikat')->display(function () {
$skips = ["[", "]", "\""];
$certificate = LandCertificate::where('data_order_id', $this->id);
$costumerName = Costumer::where('id', $this->costumer_id);
$certificateNumberArray = $certificate->pluck('number') ?? null;
$temp1 = str_replace($skips, '', $certificateNumberArray);
$certificateNumber = str_replace(',', ', ', $temp1);
if ($certificate->pluck('owner') != $costumerName->pluck('name')) {
return "<span class='text-danger'>$certificateNumber</span>";
} else
return $certificateNumber;
});实际上,该代码仅在图片编号1处显示结果,而没有像图片编号2那样链接
刀片代码:
https://github.com/z-song/laravel-admin/blob/master/resources/views/grid/table.blade.php
发布于 2019-11-28 11:13:12
我找到了解决这个问题的办法。
尝试获取数组值,然后将其返回,修改如下:
我的控制器:
$grid->column('Sertifikat')->display(function () {
$skips = ["[", "]", "\""];
$certificate = LandCertificate::where('data_order_id', $this->id);
$costumerName = Costumer::where('id', $this->costumer_id);
foreach ($certificate->pluck('number', 'id')->toArray() as $href => $text) {
if ($href != $text) {
if ($certificate->pluck('owner') != $costumerName->pluck('name')) {
$certificateDetail[] = "<a href='#' data-toggle='modal' data-target='#messageModal' data-id='{$href}' data-from='{$href}' data-title='{$href}' data-message='{$href}' data-time='{$href}'><span class='text-danger'>$text";
} else
$certificateDetail[] = "<a href='#' data-toggle='modal' data-target='#messageModal' data-id='{$href}' data-from='{$href}' data-title='{$href}' data-message='{$href}' data-time='{$href}'>$text";
} else {
$certificateDetail[] = $text;
}
}
$certificateNumberArray = $certificate->pluck('number') ?? null;
$temp1 = str_replace($skips, '', collect($certificateDetail));
$certificateNumber = str_replace(',', ', ', $temp1);
return $certificateNumber;
});结果:

发布于 2019-11-27 10:08:48
您必须使用html_entity_decode
if ($certificate->pluck('owner') != $costumerName->pluck('name')) {
return html_entity_decode("<span class='text-danger'>$certificateNumber</span>");
} else {
return $certificateNumber;
}https://stackoverflow.com/questions/59061803
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