比较两个文本文件，找出列表中的差异，并找出哪些列表值不匹配

Question

我正在使用扫描仪读取2个文本文件(可能包含重复文件)，并将它们写入arraylist。我正在比较这两个数组列表，以找出差异。当我打印输出时，我可以看到有什么不同，但我不知道哪条记录来自哪个文件(文本文件名)

text1.txt中的内容

TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,VEM,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,ZER,20190703113154,20190601000000,20190701000000,

text2.txt中的内容

TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,VEM,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,ZER,20190703113154,20190601000000,20190701000000,

代码：

Scanner prodScanner = new Scanner(prodFile);
     while (prodScanner.hasNextLine()) {
     String currentRecord = prodScanner.nextLine().trim(); 
                    if (currentRecord.length() > 0) {
                    prodRecordsFromStatement.add(currentRecord);
                  }
           }
Scanner nonProdScanner = new Scanner(nonProdFile);
while (nonProdScanner.hasNextLine()) {
            String currentRecord = nonProdScanner.nextLine().trim();  
            if (currentRecord.length() > 0) {                                   
     nonProdRecordsFromStatement.add(currentRecord);
                                }
                            }
Collection<String> result = new ArrayList<>(CollectionUtils.disjunction(prodRecordsFromStatement, nonProdRecordsFromStatement));
 List<String> resultList = new ArrayList<>(result);
 Collections.sort(resultList);

实际结果：

TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,
TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,
TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,
TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,
TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,
TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,

预期结果:我希望显示文件/列表的名称以便于理解

text2.txt,TIMESTAMP,FE,KYMA,20190703113130,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,KYMI,20190703113130,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,MLI,20190703113211,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,MLW,20190703113211,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,TDI,20190703113119,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,TDL,20190703113119,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,UMRC,20190703113154,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,UMRI,20190703113154,20190601000000,20190701000000,
text2.txt,TIMESTAMP,FE,WOLF,20190703113221,20190601000000,20190701000000,
text1.txt,TIMESTAMP,FE,WOLI,20190703113221,20190601000000,20190701000000,

Answer 1

遍历resultList检查，查看当前项是否也在prodRecordsFromStatement中。

如果是，则它来自文件1，否则它来自文件2。

Answer 2

您的解决方案需要有多高的性能？如果性能不是非常关键，并且您的列表也不长，那么您可以切换到使用subtract而不是析取。

例如。

Collection<String> resultProdRecords = new ArrayList<>(CollectionUtils.subtract(prodRecordsFromStatement, nonProdRecordsFromStatement));
Collection<String> resultNonProdRecords = new ArrayList<>(CollectionUtils.subtract(prodRecordsFromStatement, nonProdRecordsFromStatement));

resultProdRecords将包含prodRecordsFromStatement中不在nonProdRecordFromStatement中的所有行。

resultNonProdRecords将包含nonProdRecordFromStatement中不在prodRecordsFromStatement中的所有行。