我在以下代码中遇到了问题:
{-# LANGUAGE DataKinds #-}
{-# LANGUAGE TypeOperators #-}
module API where
import Data.Text
import Servant.API
import Servant
import Repository
import FileOperation
import Util
import Config
import qualified Data.Map as M
import Control.Monad.State.Strict (liftIO)
import Network.Wai.Handler.Warp
type RepositoryAPI = "repository" :> "all" :> Get '[JSON] [Repository]
:<|> "all" :> "repository" :> Get '[JSON] [Repository]
server :: Server RepositoryAPI
server = do
repositoriesMap <- liftIO $ loadFromFile repositoryMapFile
let repositories = M.elems repositoriesMap in do
return repositories
repositoryAPI :: Proxy RepositoryAPI
repositoryAPI = Proxy
app :: Application
app = serve repositoryAPI server
main :: IO ()
main = run 8081 app我得到的错误是:
API.hs:22:3: error:
• Couldn't match type ‘[a0]’ with ‘Handler [Repository]’
Expected type: Server RepositoryAPI
Actual type: Handler [Repository] :<|> [a0]
• In a stmt of a 'do' block:
repositoriesMap <- liftIO $ loadFromFile repositoryMapFile
In the expression:
do repositoriesMap <- liftIO $ loadFromFile repositoryMapFile
let repositories = ... in do return repositories
In an equation for ‘server’:
server
= do repositoriesMap <- liftIO $ loadFromFile repositoryMapFile
let ... in do ...
|
22 | repositoriesMap <- liftIO $ loadFromFile repositoryMapFile
| ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^问题是如何正确地提升,以便提升返回Servant Server类型?
发布于 2021-05-28 10:28:59
这个问题与提升无关。真正的问题是您只指定了一个Handler,但是您的服务器需要两个Handler,一个用于"repository" :> "all" :> Get '[JSON] [Repository],另一个用于"all" :> "repository" :> Get '[JSON] [Repository]。下面是第二个server的框架(用下面的代码替换现有的Here):
getRepositoryAll :: Handler [Repository]
getRepositoryAll = do
repositoriesMap <- liftIO $ loadFromFile repositoryMapFile
let repositories = M.elems repositoriesMap in do
return repositories
getAllRepository :: Handler [Repository]
getAllRepository = undefined -- fill this in
server :: Server RepositoryAPI
server = getRepositoryAll :<|> getAllRepositoryhttps://stackoverflow.com/questions/67731453
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