如何按包含数字的键对字典进行排序

Question

我有本字典：

dd = dd = {'start1': 'geo!-23.7338,-46.7876',
 'start2': 'geo!-23.7338,-46.7876',
 'start3': 'geo!-23.7338,-46.7876',
 'start4': 'geo!-23.7338,-46.7876',
 'start5': 'geo!-23.7338,-46.7876',
 'start6': 'geo!-23.7338,-46.7876',
 'start7': 'geo!-23.7338,-46.7876',
 'start8': 'geo!-23.7338,-46.7876',
 'start9': 'geo!-23.7338,-46.7876',
 'start10':'geo!-23.7338,-46.7876',
 'start11':'geo!-23.7338,-46.7876',
 'start12':'geo!-23.7338,-46.7876',
 'start13':'geo!-23.7338,-46.7876',
 'start0': 'geo!-23.7338,-46.7876'}

我想根据key对这个字典进行排序，这样它看起来就像：

dd =  {'start0': 'geo!-23.7338,-46.7876',
 'start1': 'geo!-23.7338,-46.7876',
 'start2': 'geo!-23.7338,-46.7876',
 'start3': 'geo!-23.7338,-46.7876',
 'start4': 'geo!-23.7338,-46.7876',
 'start5': 'geo!-23.7338,-46.7876',
 'start6': 'geo!-23.7338,-46.7876',
 'start7': 'geo!-23.7338,-46.7876',
 'start8': 'geo!-23.7338,-46.7876',
 'start9': 'geo!-23.7338,-46.7876',
 'start10':'geo!-23.7338,-46.7876',
 'start11':'geo!-23.7338,-46.7876',
 'start12':'geo!-23.7338,-46.7876',
 'start13':'geo!-23.7338,-46.7876'}

我一直在尝试使用以下代码：

import collections

dd = collections.OrderedDict(sorted(start_points.items()))
dd = dict(start_points)

但这就是我所得到的：

{'start0': 'geo!-23.7338,-46.7876',
 'start1': 'geo!-23.7338,-46.7876',
 'start10':'geo!-23.7338,-46.7876',
 'start11':'geo!-23.7338,-46.7876',
 'start12':'geo!-23.7338,-46.7876',
 'start13':'geo!-23.7338,-46.7876',
 'start2': 'geo!-23.7338,-46.7876',
 'start3': 'geo!-23.7338,-46.7876',
 'start4': 'geo!-23.7338,-46.7876',
 'start5': 'geo!-23.7338,-46.7876',
 'start6': 'geo!-23.7338,-46.7876',
 'start7': 'geo!-23.7338,-46.7876',
 'start8': 'geo!-23.7338,-46.7876',
 'start9': 'geo!-23.7338,-46.7876'}

如果有人知道如何做到这一点，我将非常感谢您的帮助。

Answer 1

对于您的用例，以下代码应该可以完成此工作：

 dd = {'start1': 'geo!-23.7338,-46.7876',
 'start2': 'geo!-23.7277,-46.7609',
 'start3': 'geo!-23.7244,-46.7556',
 'start4': 'geo!-23.7247,-46.7546',
 'start5': 'geo!-23.7251,-46.7606',
 'start6': 'geo!-23.7234,-46.7645',
 'start7': 'geo!-23.7181,-46.7644',
 'start8': 'geo!-23.6992,-46.7691',
 'start9': 'geo!-23.7006,-46.7678',
 'start10': 'geo!-23.69,-46.768',
 'start11': 'geo!-23.6909,-46.7688',
 'start12': 'geo!-23.6885,-46.7691',
 'start13': 'geo!-23.6854,-46.7702',
 'start0': 'geo!-23.6702,-46.6954'}
 
 
import collections

dd = collections.OrderedDict(sorted(dd.items(), key=lambda x: int(x[0][5:])))
dd = dict(dd)
print(dd)