创建sample_data:
norm_power <- rnorm(2298)
phoneme <- c("t", "v", "s", "p")
intensity <- c("loud", "soft")
unique_ID <- as.factor(rep(c("elec1", "elec2", "elec3", "elec4", "elec5", "elec6", "elec7",
"elec8", "elec9", "elec10"), length.out = 2298))
Subject <- as.factor(rep(c("DBS1", "DBS2", "DBS3", "DBS4"), length.out = 2298))
sample_data <- data.frame(norm_power, unique_ID, Subject, stringsAsFactors = FALSE)
sample_data$intensity[sample(1:nrow(sample_data), nrow(sample_data), FALSE)] <- rep(intensity, c(1149,1149))
sample_data$phoneme[sample(1:nrow(sample_data), nrow(sample_data), FALSE)] <- rep(phoneme, c(574, 574, 575, 575))我正在尝试对样本数据的多个子集执行方差分析并提取系数-参见上文。当我将数据集过滤成单独的电极(即"elec1")时,我能够得到一个结果(参见输出):
sample_data_elec1 <- filter(sample_data, unique_ID == "elec1")
output <-ezANOVA(dv = norm_power, within=.(phoneme, intensity), wid=Subject, data=sample_data_elec1)然而,当我试图一次在sample_data的多个“子集”上完成类似的操作时,我只为所有操作生成NAs。参见下面的'anova_data‘:
get_coefs <-function(d){
output <-ezANOVA(dv = norm_power, within=.(phoneme, intensity), wid=Subject, data=d)
tibble('phoneme_F' = output[["ANOVA"]][[4]][1], "phoneme_pval" = output[["ANOVA"]][[5]][1],
"intensity_F" = output[["ANOVA"]][[4]][2], "intensity_pval" = output[["ANOVA"]][[5]][2],
"interact_F" = output[["ANOVA"]][[4]][3], "interact_pval"= output[["ANOVA"]][[5]][3])
}
anova_data <- sample_data %>%
group_by(unique_ID) %>%
do({get_coefs(.)}) %>%
ungroup()提前感谢您的帮助-请让我知道,如果我可以进一步澄清!
发布于 2020-03-05 07:24:19
您会得到这个错误,因为您正在运行重复测量anova的测试。它有一个非常严格的设计,使用来自this website的示例
library(ez)
bilingual=read.delim("http://coltekin.net/cagri/R/data/bilingual.txt")
# this works
ezANOVA(data=bilingual,dv=mlu,wid=.(subj),
within=.(language, age), between=gender)你可以看到,对于每个受试者,你实际上只有一次测量之前/之后或每个因素的组合。
table(bilingual$age,bilingual$language,bilingual$subj)
, , = 1
home.only school
firstgrade 1 1
preschool 1 1
secondgrade 1 1
, , = 2
home.only school
firstgrade 1 1
preschool 1 1
secondgrade 1 1返回到您的示例,您需要使用within_full,因为您有多个度量,您的一些示例数据集可以工作,但您可以看到有一些抱怨,这是理所当然的,因为该设计不适用于此测试:
output <-ezANOVA(dv = norm_power,between=.(phoneme, intensity), within_full=.(phoneme, intensity), wid=.(Subject), data=droplevels(sample_data_elec1))而且,根据重复测量,您还缺少我在上面为您填写的间隔效果。现在,如果您的研究或测试不是针对repeated measure anova的,那么只需将您想要测试的所有变量放在以下各项之间:
output <-ezANOVA(dv = norm_power,between=.(phoneme, intensity), wid=.(Subject), data=droplevels(sample_data_elec1))https://stackoverflow.com/questions/60531554
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