应用程序正在运行fine...just数据未显示...我已经添加了用户电子邮件在登录后显示,并且在登录活动中我已经添加了
FirebaseDatabase.getInstance().getReference().child("aj").child("name").setValue("aditya");但在实时数据库中,数据不会显示,以防..i在尝试后等待半个小时,所有things..network也是好的。数据库中的数据库picture of database规则之前是
{
"rules": {
".read": "now < 1625337000000", // 2021-7-4
".write": "now < 1625337000000", // 2021-7-4
}
}我读到这应该是真的,所以现在rules
并且added_firebase在初始化时给出了错误
FirebaseDatabase mDatabase;
mDatabase = FirebaseDatabase.getInstance().getReference();android studio想要像这样改变mDataBase的类型,现在不给出错误
DatabaseReference mDatabase;
mDatabase = FirebaseDatabase.getInstance().getReference();app gradle文件
plugins {
id 'com.android.application'
id 'com.google.gms.google-services'
}
android {
compileSdkVersion 30
buildToolsVersion "30.0.3"
defaultConfig {
applicationId "com.example.firebase0"
minSdkVersion 16
targetSdkVersion 30
versionCode 1
versionName "1.0"
testInstrumentationRunner "androidx.test.runner.AndroidJUnitRunner"
}
buildTypes {
release {
minifyEnabled false
proguardFiles getDefaultProguardFile('proguard-android-optimize.txt'), 'proguard-rules.pro'
}
}
compileOptions {
sourceCompatibility JavaVersion.VERSION_1_8
targetCompatibility JavaVersion.VERSION_1_8
}
}
dependencies {
implementation 'androidx.appcompat:appcompat:1.3.0'
implementation 'com.google.android.material:material:1.3.0'
implementation 'androidx.constraintlayout:constraintlayout:2.0.4'
implementation 'com.google.firebase:firebase-auth:21.0.1'
implementation 'com.google.firebase:firebase-database:20.0.0'
testImplementation 'junit:junit:4.+'
androidTestImplementation 'androidx.test.ext:junit:1.1.2'
androidTestImplementation 'androidx.test.espresso:espresso-core:3.3.0'
}MainActivity.java //不适用于单个子代,即FirebaseDatabase.getInstance().getReference().child("aj").child("name").setValue("aditya");,也不适用于map .searched it...tried隐名模式,不同浏览器,数据库中devices...still为空
package com.example.firebase0;
import androidx.annotation.NonNull;
import androidx.appcompat.app.AppCompatActivity;
import android.content.Intent;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.Toast;
import com.google.android.gms.tasks.OnFailureListener;
import com.google.android.gms.tasks.OnSuccessListener;
import com.google.firebase.auth.FirebaseAuth;
import com.google.firebase.database.DatabaseReference;
import com.google.firebase.database.FirebaseDatabase;
import java.util.HashMap;
public class MainActivity extends AppCompatActivity {
private Button logout;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
logout= findViewById(R.id.logout_button);
// FirebaseDatabase mDatabase;
// mDatabase = FirebaseDatabase.getInstance().getReference();
logout.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
FirebaseAuth.getInstance().signOut();
Toast.makeText(MainActivity.this,"logged out successfully",Toast.LENGTH_SHORT).show();
startActivity(new Intent(MainActivity.this, StartActivity.class));
}
});
//FirebaseDatabase.getInstance().getReference().child("aj").child("name").setValue("aditya");
//yha aj branch ka name child hai uski value aditya
// agr ek branch ke ek se jada child bnane to hashmap
// DatabaseReference mDatabase;
// mDatabase = FirebaseDatabase.getInstance().getReference();
HashMap<String , Object> map = new HashMap<>();
map.put("name","aj");
map.put("sirname","jain");
map.put("desh","bharat");
FirebaseDatabase.getInstance().getReference().child("aj_database").child("multiple_children").setValue(map).addOnSuccessListener(new OnSuccessListener<Void>() {
@Override
public void onSuccess(Void aVoid) {
Toast.makeText(MainActivity.this,"Posted are Success",Toast.LENGTH_SHORT).show();
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
Toast.makeText(MainActivity.this,"Posted are Failed\n"+e,Toast.LENGTH_SHORT).show();
}
});;
}
}发布于 2021-06-05 02:58:00
添加onSuccessListener以了解写入是否已完成。
HashMap<String , Object> map = new HashMap<>();
map.put("name","aj");
map.put("sirname","jain");
map.put("desh","bharat");
mDatabase.child("aj database").child("multiple children").setValue(map)
.addOnSuccessListener(new OnSuccessListener<Void>() {
@Override
public void onSuccess(Void aVoid) {
// Write was successful!
// ...
}
})
.addOnFailureListener(new OnFailureListener() {
@Override
public void onFailure(@NonNull Exception e) {
// Write failed
// ...
}
});发布于 2021-06-05 02:58:27
FirebaseDatabase.getInstance().getReference().child("aj database").child("multiple children").setValue(map);
有关follow this的更多信息
发布于 2021-06-05 04:06:49
public class User { // Create user-class
public String name;
public String surname;
public String desh;
public User {}
public User(String name, String surname, String desh) {
this.name = name;
this.surname = surname;
this.desh = desh;
}
@Exclude
public Map<String, Object> toMap() {
HashMap<String, Object> result = new HashMap<>();
result.put("name", name);
result.put("surname", surname);
result.put("desh", desh);
return result;
}
}
public class MainActivity extends AppCompatActivity {
// ...
FirebaseDatabase mDatabase;
@Override
protected void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_main);
mDatabase = FirebaseDatabase.getInstance().getReference();
// ...
writeNewUser("aj", "jain", "bharat");
}
// method to save new user
private void writeNewUser(String name, String surname, String desh) {
String userKey = mDatabase.child("users").push().getKey(); // a unique user key
User user = new User(name, surname, desh);
Map<String, Object> userValues = user.toMap();
mDatabase.updateChildren(new HashMap<String, Object>().put("/users/" + userKey, userValues));
}
}https://stackoverflow.com/questions/67842550
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