尝试将多个字符串数组解析为数字

Question

有没有一种方法可以遍历每个Oracle endpnt数组并将字符串解析为数字，同时仍然保持Oracle endpnt数组的顺序。

代码

var oracleTitle= ['oracle1','oracle2','oracle3','oracle4']
var oracleEndpnt = [['1','3'],['1','2'],['1','3'],[]]


function Oracle(name, endpnt) {
  this.name = name;
  this.endpnt = endpnt

}

var oracles = []

for(var i=0;i<oracleTitle.length;i++) {

  oracles.push(new Oracle(oracleTitle[i],oracleEndpnt[i]))

}

console.log(oracles)

结果

[
  Oracle { name: 'oracle1', endpnt: [ '1', '3' ] },
  Oracle { name: 'oracle2', endpnt: [ '1', '2' ] },
  Oracle { name: 'oracle3', endpnt: [ '1', '3' ] },
  Oracle { name: 'oracle4', endpnt: [] }
]

Answer 1

如果不想更改所有代码，可以为第二个数组运行一个map

var oracleTitle= ['oracle1','oracle2','oracle3','oracle4']
var oracleEndpnt = [['1','3'],['1','2'],['1','3'],[]]


function Oracle(name, endpnt) {
  this.name = name;
  this.endpnt = endpnt

}

var oracles = []

for(var i=0;i<oracleTitle.length;i++) {
// Change this part
  oracles.push(new Oracle(oracleTitle[i],oracleEndpnt[i].map(num => parseInt(num))));

}

console.log(oracles)

Answer 2

如果我理解正确的话，应该这样做：

​

var oracles = [
  { name: 'oracle1', endpnt: [ '1', '3' ] },
  { name: 'oracle2', endpnt: [ '1', '2' ] },
  { name: 'oracle3', endpnt: [ '1', '3' ] },
  { name: 'oracle4', endpnt: [] }
]

var r = oracles.map(x => {
  x.endpnt = x.endpnt.map(z => Number(z))
  return x
})

console.log(r)

​

Answer 3

​

var oracleTitle= ['oracle1','oracle2','oracle3','oracle4']
var oracleEndpnt = [['1','3'],['1','2'],['1','3'],[]]
function Oracle(name, endpnt) { this.name = name; this.endpnt = endpnt }

var oracles = oracleTitle.map((s, i) => new Oracle(s, oracleEndpnt[i].map(Number)))

console.log( JSON.stringify(oracles) )

​