在python中从函数外部访问函数变量

Question

我有一个python函数，希望从函数外部检索一个值。如何在不使用全局变量的情况下实现这一点。我有一个想法，如果python中的函数是对象，那么这可能是一个正确的解决方案？

def check_difficulty():
    if (difficulty == 1):
        check_difficulty.tries = 10
    elif (difficulty == 2):
        check_difficulty.tries = 5
    elif (difficulty == 3):
        check_difficulty.tries = 3


try:
    difficulty = int(input("Choose your difficulty: "))
    check_difficulty()

except ValueError:
    difficulty = int(input("Type a valid number: "))
    check_difficulty()

while check_difficulty.tries > 0:

我刚接触python，所以请允许我...

Answer 1

def check_difficulty(difficulty):
    if (difficulty == 1):
        return 10
    elif (difficulty == 2):
        return 5
    elif (difficulty == 3):
        return 3

tries = 0
while tries > 0:
    difficulty = int(input("Choose your difficulty: "))

    tries = check_difficulty(difficulty)
    tries = tries - 1

Answer 2

如果使用while循环，并以结构化的方式将所有内容放入其中，则不需要函数。

Answer 3

您可以将其更改为一个类，以获取您的尝试：

class MyClass:
  def __init__(self):
    self.tries = 0
  def check_difficulty(self, difficulty):
    if (difficulty == 1):
        self.tries = 10
    elif (difficulty == 2):
        self.tries = 5
    elif (difficulty == 3):
        self.tries = 3

ch = MyClass()

try:
    difficulty = int(input("Choose your difficulty: "))
    ch.check_difficulty(difficulty)

except ValueError:
    difficulty = int(input("Type a valid number: "))
    ch.check_difficulty(difficulty)


ch.tries
# 5