如何在pygame中使用递归绘制矩形来制作表格？

Question

我正在尝试用pygame中的递归创建一个类似于excel文档的外观。我得到了第一个if语句来填充屏幕的第一行，并希望它每次都下降50 (我的矩形的高度)，并继续前进，直到它再次命中屏幕的边缘，完全填满屏幕。我做了另一个for循环来尝试这一点，但是它在(0,0)处停止并遗漏了一个矩形，有没有办法在一个循环中做到这一点，这样屏幕就会充满并产生一堆列和行？谢谢。

 """
    Recursively draw rectangles.
    Sample Python/Pygame Programs
    Simpson College Computer Science
    http://programarcadegames.com/
    http://simpson.edu/computer-science/
    """
    import pygame
    # Colors
    BLACK = (0, 0, 0)
    WHITE = (255, 255, 255)
    def recursive_draw(x, y, width, height):
        """ Recursive rectangle function. """
        pygame.draw.rect(screen, BLACK,
        [x, y, width, height],
        1)
        # Is the rectangle wide enough to draw again?
        if(x < 750):
            # Scale down
            x += 150
            y = 0
            width = 150
            height = 50
            # Recursively draw again
            recursive_draw(x, y, width, height)
        if (x < 750):
            # Scale down
            x += 0
            y += 50
            width = 150
            height = 50
            # Recursively draw again
            recursive_draw(x, y, width, height)
    pygame.init()
    # Set the height and width of the screen
    size = [750, 500]
    screen = pygame.display.set_mode(size)
    pygame.display.set_caption("My Game")
    # Loop until the user clicks the close button.
    done = False
    # Used to manage how fast the screen updates
    clock = pygame.time.Clock()
    # -------- Main Program Loop -----------
    while not done:
        for event in pygame.event.get():
            if event.type == pygame.QUIT:
                done = True
        # Set the screen background
        screen.fill(WHITE)
        # ALL CODE TO DRAW SHOULD GO BELOW THIS COMMENT
        recursive_draw(0, 0, 150, 50)
        # ALL CODE TO DRAW SHOULD GO ABOVE THIS COMMENT
        # Go ahead and update the screen with what we've drawn.
        pygame.display.flip()
        # Limit to 60 frames per second
        clock.tick(60)
        # Be IDLE friendly. If you forget this line, the program will 'hang'
        # on exit.
    pygame.quit()

Answer 1

我首先添加一个基本情况，这样当到达屏幕底部时，函数就会返回。将width添加到x，直到到达右侧，当它在右侧时，递增y += height并重置x = 0以开始绘制下一行。

import pygame


BLACK = (0, 0, 0)
WHITE = (255, 255, 255)

def recursive_draw(x, y, width, height):
    """Recursive rectangle function."""
    pygame.draw.rect(screen, BLACK, [x, y, width, height], 1)
    if y >= 500:  # Screen bottom reached.
        return
    # Is the rectangle wide enough to draw again?
    elif x < 750-width:  # Right screen edge not reached.
        x += width
        # Recursively draw again.
        recursive_draw(x, y, width, height)
    else:
        # Increment y and reset x to 0 and start drawing the next row.
        x = 0
        y += height
        recursive_draw(x, y, width, height)


pygame.init()
size = [750, 500]
screen = pygame.display.set_mode(size)
clock = pygame.time.Clock()
screen.fill(WHITE)
recursive_draw(0, 0, 150, 50)

done = False
while not done:
    for event in pygame.event.get():
        if event.type == pygame.QUIT:
            done = True

    pygame.display.flip()
    clock.tick(60)


pygame.quit()

使用嵌套的for循环来绘制网格会更容易：

def draw_grid(x, y, width, height, size):
    for y in range(0, size[1], height):
        for x in range(0, size[0], width):
            pygame.draw.rect(screen, BLACK, [x, y, width, height], 1)