PowerShell & Get-Aduser -in，-contains运算符作为-match运算符无法获得正确的结果

Question

我不知道为什么-in和-contains运算符不能得到与-match运算符相同的正确结果。

下面是代码。

  $user = @( "sysmon","srvctableau","ParkerE", "NguyenDi")
    
    $depart = get-aduser -filter "enabled -eq 'false'" -properties * |  Select -Property SamAccountName
    
    ForEach ($item in $user) 
    {
        if ($item -in $depart) { Write-Output "-in $item  departed" }
        else{ Write-Output "-in $item  is employee" }   
    } 
    
    ForEach ($item in $user) 
    {
        if ($depart -contains $item) { Write-Output " -contains $item  departed" }
        else{ Write-Output "-contains $item  is employee" } 
    } 
    
    ForEach ($item in $user) 
    {
        if ($depart -match $item) { Write-Output "-match $item  departed" }
        else{ Write-Output "-match $item  is employee" }    
    } 

NguyenDi是员工，srvctableau是员工，sysmon已离职，sysmon已离职

谢谢!

Answer 1

-in和-contains是用于检查value是否存在于collection中的运算符，在本例中，您将比较object[]和value。

您可以这样做：

$depart = (Get-ADUser -filter "enabled -eq 'false'").sAMAccountName

# OR

$depart = Get-ADUser -filter "enabled -eq 'false'" |
          Select-Object -ExpandProperty sAMAccountName

或者这样：

if ($item -in $depart.sAMAccountName){ ... }

# AND

if ($depart.sAMAccountName -contains $item){ ... }

这里有一个例子，说明了你正在尝试做什么以及失败的原因：

PS /> $test = 'one','two','three' | foreach { [pscustomobject]@{Value = $_} }

PS /> $test

Value
-----
one  
two  
three

PS /> $test -contains 'one'
False

PS /> 'one' -in $test
False

PS /> $test.GetType()

IsPublic IsSerial Name                                     BaseType                                                                                                       
-------- -------- ----                                     --------                                                                                                       
True     True     Object[]                                 System.Array                                                                                                   

PS /> $test.Value -contains 'one'
True

PS /> 'one' -in $test.Value
True