我是R的初学者。我需要转移一些Eviews代码到R。有一些循环代码来添加10个或更多的列\变量与一些函数在Eviews的数据。
下面是eviews估算平减指数的示例代码:
for %x exp con gov inv cap ex im
frml def_{%x} = gdp_{%x}/gdp_{%x}_r*100
next 我使用了dplyr包并使用了mutate函数。但是很难添加很多变量。
library(dplyr)
nominal_gdp<-rnorm(4)
nominal_inv<-rnorm(4)
nominal_gov<-rnorm(4)
nominal_exp<-rnorm(4)
real_gdp<-rnorm(4)
real_inv<-rnorm(4)
real_gov<-rnorm(4)
real_exp<-rnorm(4)
df<-data.frame(nominal_gdp,nominal_inv,
nominal_gov,nominal_exp,real_gdp,real_inv,real_gov,real_exp)
df<-df %>% mutate(deflator_gdp=nominal_gdp/real_gdp*100,
deflator_inv=nominal_inv/real_inv,
deflator_gov=nominal_gov/real_gov,
deflator_exp=nominal_exp/real_exp)
print(df)请帮我在R中循环一下。
发布于 2019-08-21 17:36:17
答案是你的数据并不像它应该的那样“整洁”。
这就是您所拥有的(为清楚起见,添加了一个观察ID ):
library(dplyr)
df <- data.frame(nominal_gdp = rnorm(4),
nominal_inv = rnorm(4),
nominal_gov = rnorm(4),
real_gdp = rnorm(4),
real_inv = rnorm(4),
real_gov = rnorm(4))
df <- df %>%
mutate(obs_id = 1:n()) %>%
select(obs_id, everything())这就给出了:
obs_id nominal_gdp nominal_inv nominal_gov real_gdp real_inv real_gov
1 1 -0.9692060 -1.5223055 -0.26966202 0.49057546 2.3253066 0.8761837
2 2 1.2696927 1.2591910 0.04238958 -1.51398652 -0.7209661 0.3021453
3 3 0.8415725 -0.1728212 0.98846942 -0.58743294 -0.7256786 0.5649908
4 4 -0.8235101 1.0500614 -0.49308092 0.04820723 -2.0697008 1.2478635考虑一下,如果你有,在df2中
obs_id variable real nominal
1 1 gdp 0.49057546 -0.96920602
2 2 gdp -1.51398652 1.26969267
3 3 gdp -0.58743294 0.84157254
4 4 gdp 0.04820723 -0.82351006
5 1 inv 2.32530662 -1.52230550
6 2 inv -0.72096614 1.25919100
7 3 inv -0.72567857 -0.17282123
8 4 inv -2.06970078 1.05006136
9 1 gov 0.87618366 -0.26966202
10 2 gov 0.30214534 0.04238958
11 3 gov 0.56499079 0.98846942
12 4 gov 1.24786355 -0.49308092那么你想要做的就很简单了:
df2 %>% mutate(deflator = real / nominal) obs_id variable real nominal deflator
1 1 gdp 0.49057546 -0.96920602 -0.50616221
2 2 gdp -1.51398652 1.26969267 -1.19240392
3 3 gdp -0.58743294 0.84157254 -0.69801819
4 4 gdp 0.04820723 -0.82351006 -0.05853872
5 1 inv 2.32530662 -1.52230550 -1.52749012
6 2 inv -0.72096614 1.25919100 -0.57256297
7 3 inv -0.72567857 -0.17282123 4.19901294
8 4 inv -2.06970078 1.05006136 -1.97102841
9 1 gov 0.87618366 -0.26966202 -3.24919196
10 2 gov 0.30214534 0.04238958 7.12782060
11 3 gov 0.56499079 0.98846942 0.57158146
12 4 gov 1.24786355 -0.49308092 -2.53074800因此,问题变成了:我们如何获得与dplyr兼容的漂亮的data.frame。
您需要使用tidyr::gather收集数据。但是,因为您需要收集两组变量(实际值和标称值),所以这并不简单。我已经完成了两个步骤,不过可能还有更好的方法。
real_vals <- df %>%
select(obs_id, starts_with("real")) %>%
# the line below is where the magic happens
tidyr::gather(variable, real, starts_with("real")) %>%
# extracting the variable name (by erasing up to the underscore)
mutate(variable = gsub(variable, pattern = ".*_", replacement = ""))
# Same thing for nominal values
nominal_vals <- df %>%
select(obs_id, starts_with("nominal")) %>%
tidyr::gather(variable, nominal, starts_with("nominal")) %>%
mutate(variable = gsub(variable, pattern = ".*_", replacement = ""))
# Merging them... Now we have something we can work with!
df2 <-
full_join(real_vals, nominal_vals, by = c("obs_id", "variable"))注意合并时观察id的重要性。
发布于 2019-08-21 17:39:46
我们可以grep匹配的名称,并进行排序:
x <- colnames(df)
df[ sort(x[ (grepl("^nominal", x)) ]) ] /
df[ sort(x[ (grepl("^real", x)) ]) ] * 100类似地,如果对列进行了排序,那么我们只需:
df[ 1:4 ] / df[ 5:8 ] * 100发布于 2019-08-21 18:41:20
我们可以使用purrr::map_dfc遍历列名,然后对选定的列(即与nms中的当前名称匹配的列)应用自定义函数。
library(dplyr)
library(purrr)
#Replace anything before _ with empty string
nms <- unique(sub('.*_','',names(df)))
#Use map if you need the ouptut as a list not a dataframe
map_dfc(nms, ~deflator_fun(df, .x))自定义函数
deflator_fun <- function(df, x){
#browser()
nx <- paste0('nominal_',x)
rx <- paste0('real_',x)
select(df, matches(x)) %>%
mutate(!!paste0('deflator_',quo_name(x)) := !!ensym(nx) / !!ensym(rx)*100)
}
#Test
deflator_fun(df, 'gdp')
nominal_gdp real_gdp deflator_gdp
1 -0.3332074 0.181303480 -183.78433
2 -1.0185754 -0.138891362 733.36121
3 -1.0717912 0.005764186 -18593.97398
4 0.3035286 0.385280401 78.78123注意:了解有关quo_name、!!和ensym的更多信息,它们是使用dplyr here进行编程的工具。
https://stackoverflow.com/questions/57587865
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