Dart未处理的异常: FormatException:无效的基数-10数字(位于字符1)

Question

我正试着从互联网上获取一些数据。所以我提出了一个天气网站的API请求。但我得到了以下异常-未处理的异常: FormatException:无效的基数-10数字(在字符1处)。这是错误代码：

    [VERBOSE-2:shell.cc(242)] Dart Unhandled Exception: FormatException: Invalid radix-10 number (at character 1)
//uri.openweathermap.org/data/2.5/weather?lat=35&lon=139&appid=4659036c3236...
^
, stack trace: #0      int._throwFormatException (dart:core-patch/integers_patch.dart:131:5)
#1      int._parseRadix (dart:core-patch/integers_patch.dart:157:16)
#2      int._parse (dart:core-patch/integers_patch.dart:100:12)
#3      int.parse (dart:core-patch/integers_patch.dart:63:12)
#4      _Uri._makeHttpUri (dart:core/uri.dart:1591:49)
#5      new _Uri.https (dart:core/uri.dart:1462:12)
#6      _LoadingScreenState.getData (package:clima/screens/loading_screen.dart:25:49)
#7      _LoadingScreenState.build (package:clima/screens/loading_screen.dart:37:5)
#8      StatefulElement.build (package:flutter/src/widgets/framework.dart:4612:27)
#9      ComponentElement.performRebuild (package:flutter/src/widgets/framework.dart:4495:15)
#10     StatefulElement.performRebuild (package:flutter/src/widgets/framework.dart:4<…>

这是与之配套的代码：

import 'package:flutter/material.dart';
import 'package:clima/services/location.dart';
import 'package:http/http.dart' as http;

class LoadingScreen extends StatefulWidget {
  @override
  _LoadingScreenState createState() => _LoadingScreenState();
}

class _LoadingScreenState extends State<LoadingScreen> {
  @override
  void initState() {
    super.initState();
    getLocation();
  }

  void getLocation() async {
    Location location = Location();
    await location.getCurrentLocation();
    print(location.latitude);
    print(location.longitude);
  }

  void getData() async {
    http.Response response = await http.get(Uri.https(
        'https://uri.openweathermap.org/data/2.5/weather?lat=35&lon=139&appid=4659036c323608514eb865c174726965',
        'albums/1'));

    if (response.statusCode == 200) {
      String data = response.body;
      print(data);
    } else {}
  }

  @override
  Widget build(BuildContext context) {
    getData();
    return Scaffold();
  }
}

Answer 1

我遇到了这个问题，我解决了从网址中删除https://的问题。

如果出于某种原因需要将https://保留在字符串中，请将Uri.https替换为Uri.parse

你可以在这里看到一个完整的例子：https://flutter.dev/docs/cookbook/networking/fetch-data

Answer 2

该错误是Dart试图将字符串转换(解析)为整数，但该字符串不是有效的基数10 (?)数。

示例：

print(int.parse('//ten'));

将抛出

print(int.parse('10'));

应该行得通。

我猜Uri.https正在尝试int.parse()，以防您提供的地址是IP/IPv6地址(?)以及它被不正确的提供格式卡住了，正如jamesdin在评论中提到的那样。

Answer 3

使用以下代码：

...
final uri = Uri.parse('your url here');

http.Response response = await http.get(uri);
...

给我解决了这个问题