我正在试图弄清楚如何将UNION与相同的JOIN一起使用,而不陷入#2014 -命令不同步。
我已经创建了四个简单的表,并为它们编写了简化的代码。主要的想法是得到每一把剑,枪和帽子,它们的名字都是‘最好的’,如果它们的主人很酷的话。
SELECT pirate_id, sword, null AS gun, null AS hat, legs = 1 AS is_cool FROM swords as t1
LEFT JOIN
(SELECT legs, pirate_id as pid FROM body_parts) AS t2
ON t1.pirate_id = t2.pid
WHERE sword LIKE '%best%'
UNION
SELECT pirate_id, null AS sword, gun, null AS hat, legs = 1 AS is_cool FROM guns as t3
LEFT JOIN
(SELECT legs, pirate_id as pid FROM body_parts) AS t4
ON t3.pirate_id = t4.pid
WHERE gun LIKE '%best%'
UNION
SELECT pirate_id, null AS sword, null AS gun, hat, legs = 1 AS is_cool FROM hats as t5
LEFT JOIN
(SELECT legs, pirate_id as pid FROM body_parts) AS t6
ON t5.pirate_id = t6.pid
WHERE hat LIKE '%best%'
ORDER BY is_cool DESC, pirate_id ASC目前,每次我必须联合时,我都必须重复加入。我希望有更好的方法..。
表创建:
CREATE TABLE IF NOT EXISTS `body_parts` (
`pirate_id` int(11) NOT NULL,
`legs` int(11) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `body_parts` (`pirate_id`, `legs`) VALUES
(1, 0),
(2, 1),
(3, 2);
CREATE TABLE IF NOT EXISTS `guns` (
`pirate_id` int(11) NOT NULL,
`gun` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `guns` (`pirate_id`, `gun`) VALUES
(1, 'best 1');
CREATE TABLE IF NOT EXISTS `hats` (
`pirate_id` int(11) NOT NULL,
`hat` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `hats` (`pirate_id`, `hat`) VALUES
(2, 'best 2');
CREATE TABLE IF NOT EXISTS `swords` (
`pirate_id` int(11) NOT NULL,
`sword` varchar(100) NOT NULL
) ENGINE=InnoDB DEFAULT CHARSET=utf8;
INSERT INTO `swords` (`pirate_id`, `sword`) VALUES
(3, 'best 3');发布于 2019-03-26 15:24:16
您可以使用单个左连接来更改使用子查询
select t1.pirate_id, t1.sword, t1.gun, t1.hat, t2.legs=1 is_cool
from (
SELECT pirate_id, sword, null AS gun, null AS hat
FROM swords
WHERE sword LIKE '%best%'
UNION
SELECT pirate_id, null, gun, null
FROM guns
WHERE gun LIKE '%best%'
UNION
SELECT pirate_id, null, null, hat
FROM hats
WHERE hat LIKE '%best%'
) t1
LEFT JOIN (
SELECT legs, pirate_id
FROM body_parts
) t2 ON t2.pirate_id = t1.pirate_id
ORDER BY is_cool DESC, pirate_id ASChttps://stackoverflow.com/questions/55351351
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