("person"
("child-1"
("grandchild-1a" "grandchild-1a-value"
"grandchild-1b" "grandchild-1b-value")
"child-2"
("grandchild-2a" "grandchild-2a-value"
"grandchild-2b" "grandchild-2b-value")))如何将"grandchild-1b-value"修改为"grandchild-1b-value-modified"?关键字是字符串。
或者,除了新值之外,如何创建一个等价的嵌套plist的新var?
下面是我是如何用plist结束的。我将来自drakma请求的响应提供给yason:parse
(let ((stream (drakma:http-request endpoint
:method :post
:want-stream t
:content-type "application/json"
:content request)))
(setf (flexi-streams:flexi-stream-external-format stream) :utf-8)
(let ((response (yason:parse stream :object-as :plist)))
***HERE***))发布于 2021-06-14 01:49:52
CL-USER 346 > (pprint
(subst "grandchild-1b-value-modified"
"grandchild-1b-value"
'("person"
("child-1"
("grandchild-1a" "grandchild-1a-value"
"grandchild-1b" "grandchild-1b-value")
"child-2"
("grandchild-2a" "grandchild-2a-value"
"grandchild-2b" "grandchild-2b-value")))
:test #'equal))
("person"
("child-1"
("grandchild-1a"
"grandchild-1a-value"
"grandchild-1b"
"grandchild-1b-value-modified")
"child-2"
("grandchild-2a"
"grandchild-2a-value"
"grandchild-2b"
"grandchild-2b-value")))https://stackoverflow.com/questions/67961013
复制相似问题