我有一个代码用来追踪邀请。如果没有提到的成员,那么它将显示您自己的邀请,但如果有,它将显示该成员的邀请。
@client.command()
async def invites(ctx, user = None):
if user == None:
totalInvites = 0
for i in await ctx.guild.invites():
if i.inviter == ctx.author:
totalInvites += i.uses
await ctx.send(f"You've invited {totalInvites} member{'' if totalInvites == 1 else 's'} to the server!")
else:
totalInvites = 0
for i in await ctx.guild.invites():
totalInvites += i.uses
member = ctx.message.guild.get_member_named(user)
await ctx.send(f"{member} has invited {totalInvites} member{'' if totalInvites == 1 else 's'} to the server!")没有错误,相反,它只是垃圾邮件:没有邀请__成员到服务器!(__是一个随机数。)
如果没有提到的人,它可以工作。我怎样才能发送上述人的邀请函数量呢?为什么它会向邮件发送垃圾邮件?
谢谢。
发布于 2020-11-13 05:12:21
你好像忘了检查你的邀请作者是否正确。您遍历了invites,但没有if i.inviter == member。
修复后的代码为:
@client.command()
async def invites(ctx, user = None):
if user == None:
totalInvites = 0
for i in await ctx.guild.invites():
if i.inviter == ctx.author:
totalInvites += i.uses
await ctx.send(f"You've invited {totalInvites} member{'' if totalInvites == 1 else 's'} to the server!")
else:
totalInvites = 0
for i in await ctx.guild.invites():
member = ctx.message.guild.get_member_named(user)
if i.inviter == member:
totalInvites += i.uses
await ctx.send(f"{member} has invited {totalInvites} member{'' if totalInvites == 1 else 's'} to the server!")此外,它发送垃圾邮件的原因是因为您在for循环中包含了await ctx.send语句。
https://stackoverflow.com/questions/64811739
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