这是我试图完成的:我有一个graphql API端点,它返回给我一个Project对象,如下所示(删除不相关的字段):
{
"data": {
"Project": {
"id": "cjp4b84wkochq0167gpu8oa7h",
"requests": [
{
"id": "cjpbb6jcdpwj00167y4acl5a1",
"__typename": "Request"
},
{
"id": "cjpbbhlaxpwlx01675jzfyb0j",
"__typename": "Request"
},
{
"id": "cjpbbifg7pwmg0167s0ob1bm6",
"__typename": "Request"
},
],
"__typename": "Project"
}
}
}我想使用apollo-link-state向所有这些请求对象添加一个客户端字段,如下所示:
{
"data": {
"Project": {
"id": "cjp4b84wkochq0167gpu8oa7h",
"requests": [
{
"id": "cjpbb6jcdpwj00167y4acl5a1",
"expanded": false,
"__typename": "Request"
},
{
"id": "cjpbbhlaxpwlx01675jzfyb0j",
"expanded": false,
"__typename": "Request"
},
{
"id": "cjpbbifg7pwmg0167s0ob1bm6",
"expanded": false,
"__typename": "Request"
},
],
"__typename": "Project"
}
}
}这将允许我从呈现这些请求的组件中删除本地状态。问题是,当我为我的ApolloClient clientState定义默认值时,如下所示:
const client = new ApolloClient({
clientState: {
defaults: {
Project: {
__typename: 'Project',
requests: [{ __typename: 'Request', expanded: false }],
},
},
},
});Apollo将其添加为新的Project对象,而不是将其添加到现有的Project对象(具有id):
ROOT_QUERY
Project: Project
requests: [Request]
0:
expanded: false
Project({"id":"cjp4b84wkochq0167gpu8oa7h"}): Project
▾Project:cjp4b84wkochq0167gpu8oa7h当我给它提供id时,它会将"hi“字段添加到正确的项目中,但是请求仍然缺少扩展的字段。显然,给出id只对特定的项目有效。
const client = new ApolloClient({
clientState: {
defaults: {
'Project({"id":"cjp4b84wkochq0167gpu8oa7h"})': {
__typename: 'Project',
hi: true,
requests: [{ __typename: 'Request', expanded: false }],
},
},
},
});
ROOT_QUERY
Project({"id":"cjp4b84wkochq0167gpu8oa7h"}): Project
▾Project:cjp4b84wkochq0167gpu8oa7h
hi: true
requests: [Request]
0:▾Request:cjpbb6jcdpwj00167y4acl5a1
...unrelated fields
1:▾Request:cjpbbhlaxpwlx01675jzfyb0j
2:▾Request:cjpbbifg7pwmg0167s0ob1bm6我还尝试在clientState对象上使用typeDefs字段,如下所示:
typeDefs: [`
schema {
query: RootQuery
}
type RootQuery {
Project($id: ID): Project
}
type Project {
id: ID!
requests: [Request]
}
type Request {
id: ID!
expanded: Boolean
}
`],但这似乎不会改变缓存中的任何东西,我甚至不知道是否可以给它一个默认值。
也许我误解了apollo-link-state的工作原理(甚至是graphql的工作原理),任何能给我指明正确方向的答案都将不胜感激。当涉及到graphql或apollo时,我还只是个初学者。
发布于 2018-12-20 14:14:41
您需要为您的clientState配置提供客户端解析器。
const clientState = {
resolvers: {
Project {
expanded: () => false
}
}
}然后你可以像这样把它传递给你的ApolloClient
const apolloClient = new ApolloClient({ clientState });https://stackoverflow.com/questions/53749124
复制相似问题