拉取接口jsonResponse SyntaxError

Question

在尝试使用jsonResponse实现来自Codecademy的fetch API的一些代码后，我有了这个SyntaxError :我认为这只是因为jsonResponse必须被分配一个变量，因为它是一个常量：

https://www.accesstheflock.io/matchTable/.   PayTheBirdDog :      SyntaxError: Unexpected identifier 'await'. const declared variable 'jsonResponse' must have an initializer. l:234 c:0

<script>


/*
response.headers.get('Content-Type') + response.url + response.status

fetch('https://www.accesstheflock.io/matchTable/DoggingFistfuls')
.then(
        response => {
            alert(respons

e.json());
        },
        rejection => {
            alert(rejection.message);
        }
);
*/
const doggingFistfuls = async() => {
    try {

    fetch('https://www.accesstheflock.io/matchTable/DoggingFistfuls');

    if (response.ok) {
        const jsonResponse await response.json();
    } catch(error) {
        alert(error);
    }
    //if
}
}
</script>

Answer 1

您需要使用await调用fetch，并将其赋给一个变量：

const doggingFistfuls = async() => {
try {

const response = await fetch('https://www.accesstheflock.io/matchTable/DoggingFistfuls');

if (response.ok) {
    const jsonResponse = await response.json();
} catch(error) {
    alert(error);
}
//if

}}