当我试图编译我的程序时,我得到了这些错误
1>c:\users\danilo\desktop\lab2\project1\project1\main.cpp(11):error 1>c:\users\danilo\desktop\lab2\project1\project1\fighter.h(9)::'Fighter':在标识符'f1‘1>c:\users\danilo\desktop\lab2\project1\project1\之前非法使用此类型作为表达式1>c:\users\danilo\desktop\lab2\project1\project1\fighter.h(9):注意:请参见声明'Fighter’1>c:\users\danilo\desktop\lab2\project1\project1\main.cpp(11):error C2146: 1>c:\users\danilo\desktop\lab2\project1\project1\main.cpp(11):error: missing ')‘)’1>c:\users\danilo\desktop\lab2\project1\project1\main.cpp(12):(12):错误错误:语法错误:'}‘main.cpp C2059 C2143:语法错误:缺少';‘在'}’之前
我的主文件如下所示:
#include "Fighter.h"
#include "Spell.h"
#include "Player.h"
#include "Wizard.h"
#include "Collection.h"
int lastID = 0;
int main{
Fighter f1;
f1("A", 100, 100);
}; 我的Fighter.h看起来像这样
#define FIGHTER_H
#include "Card.h"
#include <string>
#include <iostream>
using namespace std;
class Fighter : public Card {
int power;
public:
virtual string getCategory() const override {
return "FIGHTER";
}
int getPower() const {
return power;
}
Fighter(string Name_, int neededEnergy_, int power_) : Card(Name_, neededEnergy_), power(power_) {}
void operator>(const Fighter& f) const {
if (this->getPower() > f.getPower()) {
cout << this->getName() << " is stronger " << endl;
}
else {
cout << f.getName() << " is stronger " << endl;
};
}
virtual void write(ostream& it) const override {
it << "(power: " << getPower() << ")";
}
};
#endif FIGHTER_H这里的问题是什么?
发布于 2019-12-05 20:30:36
您的main函数缺少括号。这
int main{应该是
int main(){此外,f1("A", 100, 100)不是构造函数调用,而是对operator()的调用,这是您所没有的。改为执行以下操作:
Fighter f1("A", 100, 100);另外,确保你的守卫是一致的。缺少一个#ifndef FIGHTER_H。
https://stackoverflow.com/questions/59195103
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