我需要找到MTD (月初至今)和年初至今的销售价值为每个项目。而且,我对需要查找销售报告的整个数据进行了筛选。根据这个日期,它应该会找到MTD和YTD的销售额。它应该按条形码对项目进行分组。例如:在我的筛选器中,如果我输入:8月21日,我应该找到当天的销售和MTD,YTD。
它可以很好地处理当前日期,但如果我使用除当前日期之外的任何日期,则MTD和YTD会有所不同
SELECT Barcode,
SUM(CASE WHEN DATE = DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), -1) THEN sales_amount ELSE 0 END) AS day_1,
SUM(CASE
WHEN MONTH(date) = (MONTH(GETDATE() - 1))
AND YEAR(date) = YEAR(GETDATE() - 1) THENsales_amount
ELSE 0
END) AS month_t,
SUM(CASE
WHEN MONTH(date) = (MONTH(GETDATE() - 1))
AND YEAR(date) = YEAR(GETDATE() - 1) - 1 THEN GL_TOTALTTC
ELSE 0
END) AS lastyear_tm,
FROM sale
WHERE type = 'FFO'
AND store = 'AE001A'
AND (DATE = DATEADD(DAY, DATEDIFF(DAY, 0, GETDATE()), -1)
OR ((MONTH(date) = (MONTH(GETDATE() - 1))
AND YEAR(date) = YEAR(GETDATE() - 1))
OR (MONTH(date) = (MONTH(GETDATE() - 1))
AND YEAR(date) = YEAR(GETDATE() - 1) - 1)))
GROUP BY barcode;发布于 2019-08-22 18:51:29
您可以使用条件聚合:
select bar_code,
sum(case when date >= dateadd(day, -1, convert(date, getdate()) then sales_amount end) as yesterday,
sum(case when month(date) = month(getdate()) and year(date) = year(getdate()) then sales_amount end) as mtd,
sum(case when year(date) = year(getdate()) then sales_amount end) as ytd
from sale
where type = 'FFO' and store = 'AE001A'
group by barcode;https://stackoverflow.com/questions/57607625
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