netcdf - CDO monmean

Question

我有一个netcdf文件，具有每日时间步长，我希望将其转换为每月时间步长。时间格式如下：

    double time(time) ;
            time:standard_name = "time" ;
            time:long_name = "time" ;
            time:bounds = "time_bnds" ;
            time:units = "days since 2000-01-01" ;
            time:calendar = "standard" ;
            time:axis = "T" ;

当我使用以下命令转换为每月时间步长时：

cdo monmean input.nc output.nc

除了时间输出很奇怪之外，一切都很正常：

 time = "2000-01-16", "2000-02-15", "2000-03-16", "2000-04-15 12",
"2000-05-16", "2000-06-15 12", "2000-07-16", "2000-08-16",
"2000-09-15 12", "2000-10-16", "2000-11-15 12", "2000-12-16";

我希望将每月值上的日期替换为每月的第一天，并删除出现的时间的奇数12。所需的输出：

 time = "2000-01-01", "2000-02-01", "2000-03-01", "2000-04-01",
"2000-05-01", "2000-06-01", "2000-07-01", "2000-08-01",
"2000-09-01", "2000-10-01", "2000-11-01", "2000-12-01";

如有任何提示，我们将不胜感激

Answer 1

cdo --timestat_date first monmean input.nc output.nc

适用于我，我希望它是有帮助的！它将时间戳放在平均周期的第一步，而默认时间戳放在中间。(如果你想做相反的事情，并把它放在窗口的最后一步，还有一个--timestat_date last )