我尝试设置state,但得到错误“钩子只能在函数组件的主体内调用”。
这是代码导入React,{ useState }从"react";
import AuthService from "../Services/AuthService";
const [Searchfile, setSearchfile] = useState([]);
AuthService.getalldata().then((res) => {
setSearchfile(res.data);
});
// const Searchfile = [
// { title: "ayam", singer: "gigi" },
// { title: "ucuk", singer: "asd" },
// ];
export default Searchfile;谁能给我解释一下为什么这是错误,以及如何修复它?:D
发布于 2020-11-19 01:05:02
尝试添加一个功能组件,并将代码粘贴到那里。
import React, { useState } from 'react';
function Example() {
const [count, setCount] = useState(0);
return (
<div>
<p> {count}</p>
<button onClick={() => setCount(count + 1)}>
click here
</button>
</div>
);
}
发布于 2020-11-19 01:39:32
您试图在功能组件外部调用useState钩子,这违反了钩子的规则。看过你的代码后,你似乎想要创建一个定制的钩子,所以我的建议是这样做:
import { useState } from 'react'
import AuthService from "../Services/AuthService";
const UseSearchFile = () => {
const [Searchfile, setSearchfile] = useState([]);
AuthService.getalldata().then((res) => {
setSearchfile(res.data);
});
return {Searchfile}
}
export default UseSearchFile 然后在需要的地方导入它,如下所示:
import UseSearchFile from ...correct path并这样称呼它:
const { Searchfile } = UseSearchFile()https://stackoverflow.com/questions/64897685
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