我需要在一个页面上的2个jquery标签,以便当您打开tabA上的链接1,它也会打开tabB上的链接1
这个是可能的吗?我使用的是同一个类,但它在单击链接时只会打开它下面的选项卡内容
谢谢你的帮助
<div id="tabA" class="tabJoined">
<ul>
<li><a href="#tabs-1">Tab 1</a>
</li>
<li><a href="#tabs-2">Tab 2</a>
</li>
<li><a href="#tabs-3">Tab 3</a>
</li>
</ul>
<div id="tabs-1">
<p>Content for Tab 1</p>
</div>
<div id="tabs-2">
<p>Content for Tab 2</p>
</div>
<div id="tabs-3">
<p>Content for Tab 3</p>
</div>
</div>
<div id="tabid"></div>
<div id="tabB" class="tabJoined">
<ul>
<li><a href="#tabs-1">Tab 1</a>
</li>
<li><a href="#tabs-2">Tab 2</a>
</li>
<li><a href="#tabs-3">Tab 3</a>
</li>
</ul>
<div id="tabs-1">
<p>Content for Tab 1</p>
</div>
<div id="tabs-2">
<p>Content for Tab 2</p>
</div>
<div id="tabs-3">
<p>Content for Tab 3</p>
</div>
</div>
<div id="tabid"></div>
<script>
$(".tabJoined").tabs({
activate: function () {
}
});
</script>发布于 2020-06-11 02:42:27
您可以在适当的选项卡上触发click事件。请考虑以下内容。
$(function() {
$(".tabJoined").tabs({
activate: function(e, ui) {
var source = $(this);
var target = $(".tabJoined").not(source);
var tInd = source.tabs("option", "active");
target.tabs("widget").find(".ui-tabs-anchor:eq(" + tInd + ")").click();
}
});
});<link rel="stylesheet" href="//code.jquery.com/ui/1.12.1/themes/base/jquery-ui.css">
<script src="https://code.jquery.com/jquery-1.12.4.js"></script>
<script src="https://code.jquery.com/ui/1.12.1/jquery-ui.js"></script>
<div id="tabA" class="tabJoined">
<ul>
<li><a href="#tabs-1">Tab 1</a>
</li>
<li><a href="#tabs-2">Tab 2</a>
</li>
<li><a href="#tabs-3">Tab 3</a>
</li>
</ul>
<div id="tabs-1">
<p>Content for Tab A-1</p>
</div>
<div id="tabs-2">
<p>Content for Tab A-2</p>
</div>
<div id="tabs-3">
<p>Content for Tab A-3</p>
</div>
</div>
<div id="tabB" class="tabJoined">
<ul>
<li><a href="#tabs-1">Tab 1</a>
</li>
<li><a href="#tabs-2">Tab 2</a>
</li>
<li><a href="#tabs-3">Tab 3</a>
</li>
</ul>
<div id="tabs-1">
<p>Content for Tab B-1</p>
</div>
<div id="tabs-2">
<p>Content for Tab B-2</p>
</div>
<div id="tabs-3">
<p>Content for Tab B-3</p>
</div>
</div>
https://stackoverflow.com/questions/62308548
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