解包数组值

Question

我正在尝试解开这个数组[0.07338447][0.92661554]

我已经找到了一种方法，但效率很低。我正在寻找更有效的方法来解决这个问题。谢谢。

i = 0
myres = [[[[0.07338447]] [[0.92661554]]]]
for  value in enumerate(myres[0]):
    print("value", value)
    for value1 in enumerate(value[1]):
        for count, value2 in enumerate(value1[1], 100):
            print(count, value2)
            print("value2", value2)
            print("I value", i)
            if (i == 0):
                ageValue = value2
                print("ageValue", ageValue)
            else:
                GenderValue = value2
                print("GenderValue", GenderValue) 
            i = i+1

Answer 1

import numpy as np

myres = [[[[0.07338447]], [[0.92661554]]]]
arr = np.array(myres).flatten()
val1, val2 = arr

Answer 2

使用numpy或者像这样简单地循环它：

myres = [[[[0.07338447]],[[0.92661554]]]]
for i in myres[0]:
    print(i[0][0])

Answer 3

您可以使用递归：

data = [[[[0.07338447]],[[0.92661554]]]]

output = []
# function used for removing nested lists in python
def removeNestings(l):
    for i in l:
        if type(i) == list:
            removeNestings(i)
        else:
            output.append(i)
    return output

print (removeNestings(data))

输出：

[0.07338447, 0.92661554]

或者仅仅使用列表理解：

def removeNestings(l):
    return sum(([x] if not isinstance(x, list) else removeNestings(x)for x in l), [])

print(removeNestings(data))