我想要条目的最后一个UID。mysql为"insertId()“。这在Extbase中是如何工作的?
$queryBuilder = GeneralUtility::makeInstance(ConnectionPool::class)->getQueryBuilderForTable($table);
$queryBuilder
->insert($table)
->values([
'test_id' => 1,
'test2_id' => 2,
]);
$queryBuilder->execute();
$queryBuilder = GeneralUtility::makeInstance(ConnectionPool::class)->getQueryBuilderForTable($table2);
$queryBuilder
->insert($table2)
->values([
'uid_local' => ?, // uid from $table
'uid_foreign' => 1
]);
$queryBuilder->execute();发布于 2019-04-03 22:06:12
您可以使用$queryBuilder->getConnection()->lastInsertId();获取最后一个插入id
因此,这将使它:
$queryBuilder = GeneralUtility::makeInstance(ConnectionPool::class)->getQueryBuilderForTable($table);
$queryBuilder
->insert($table)
->values([
'test_id' => 1,
'test2_id' => 2,
]);
$queryBuilder->execute();
$tableUid = $queryBuilder->getConnection()->lastInsertId();
$queryBuilder = GeneralUtility::makeInstance(ConnectionPool::class)->getQueryBuilderForTable($table2);
$queryBuilder
->insert($table2)
->values([
'uid_local' => $tableUid,
'uid_foreign' => 1
]);
$queryBuilder->execute();发布于 2019-04-03 22:05:39
我有点不确定在使用QueryBuilder插入新记录时它是否可用,但是Docs中的迁移指南解释了如何在新的TYPO3数据库层中迁移sql_insert_id()方法
提示:
(int)$databaseConnectionForPages->lastInsertId('pages');
https://stackoverflow.com/questions/55496980
复制相似问题