在WPF项目中,我使用方法
webBrowser.Navigate(strUrl);从服务器获取PNG图片。
将出现以下对话框:

如何无缝下载图片(没有对话框)?
发布于 2019-04-09 01:23:36
为此,您不需要使用浏览器控件。
这是一个完整的工作示例。(根据需要更改路径。)
private void Button_Click(object sender, RoutedEventArgs e)
{
WebClient client = new WebClient();
client.DownloadFileAsync(new Uri("https://www.example.com/filepath"), @"C:\Users\currentuser\Desktop\Test.png");
client.DownloadFileCompleted += Client_DownloadFileCompleted;
client.DownloadProgressChanged += Client_DownloadProgressChanged;
}
private void Client_DownloadProgressChanged(object sender, DownloadProgressChangedEventArgs e)
{
progressBar.Value = e.ProgressPercentage;
TBStatus.Text = e.ProgressPercentage + "% " + e.BytesReceived + " of " + e.TotalBytesToReceive + " received.";
}
private void Client_DownloadFileCompleted(object sender, System.ComponentModel.AsyncCompletedEventArgs e)
{
MessageBox.Show("Download Completed");
}您可以使用默认应用程序打开下载的文件,如下所示:
System.Diagnostics.Process.Start(@"C:\Users\currentuser\Desktop\Test.png");编辑:
如果您的目标只是显示png,则可以将其下载到流中,然后在image control中显示它。
完整的工作样本。
WebClient wc = new WebClient();
MemoryStream stream = new MemoryStream(wc.DownloadData("https://www.dropbox.com/s/l3maq8j3yzciedw/App%20in%205%20minutes.PNG?raw=1"));
System.Drawing.Bitmap bmp = new System.Drawing.Bitmap(stream);
bmp.Save(stream, System.Drawing.Imaging.ImageFormat.Png);
stream.Position = 0;
BitmapImage bi = new BitmapImage();
bi.BeginInit();
bi.StreamSource = stream;
bi.EndInit();
image1.Source = bi;以下是异步版本。
private void Button_Click(object sender, RoutedEventArgs e)
{
WebClient wc = new WebClient();
wc.DownloadDataAsync(new Uri("https://www.dropbox.com/s/l3maq8j3yzciedw/App%20in%205%20minutes.PNG?raw=1"));
wc.DownloadDataCompleted += Wc_DownloadDataCompleted;
}
private void Wc_DownloadDataCompleted(object sender, DownloadDataCompletedEventArgs e)
{
MemoryStream stream = new MemoryStream((byte[])e.Result);
System.Drawing.Bitmap bmp = new System.Drawing.Bitmap(stream);
bmp.Save(stream, System.Drawing.Imaging.ImageFormat.Png);
stream.Position = 0;
BitmapImage bi = new BitmapImage();
bi.BeginInit();
bi.StreamSource = stream;
bi.EndInit();
image1.Source = bi;
}https://stackoverflow.com/questions/55491530
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