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为分层抽样准备抽样分布的最佳R包函数
EN

Stack Overflow用户
提问于 2020-03-18 20:32:36
回答 1查看 204关注 0票数 2

我试图在R中准备一个演示,展示小总体的重复分层随机抽样如何导致均值的近似正态抽样分布。作为一个例子,考虑下面的R代码(它可以工作,但由于循环而非常慢)。

代码语言:javascript
复制
#Dummy population made up of dice throws - 18 per row
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
P1 <- as.data.frame(c(5,6,5,1,6,4,2,2,4,4,6,6,5,2,3,5,1,6))
P1$Zn <- 1
names(P1) <- c('Die','Zn')
Dt <- P1

P2 <- as.data.frame(c(2,5,4,5,5,5,3,3,2,5,6,1,2,5,4,3,6,1))
P2$Zn <- 2
names(P2) <- c('Die','Zn')
Dt <- rbind(Dt,P2)

# Empty dataframe to hold random draws
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Smps <- data.frame(Die = numeric(), Zn= numeric(),Drw = numeric())

# Draw stratifed samples one from each row
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
print(paste('Start','at',Sys.time()))
n <- 10000          # number of draws
r <- 2              # number of rows (the strata)
for (j in 1:n){
  # for a 2 strata
  for (i in 1:r){
    #sub set strata
    x <- subset(Dt, Dt$Zn == i)
    # random sample
    y <- x[sample(1:18,1),]
    y$Drw <- j
    #append sample
    Smps <- rbind(Smps,y)
  }
  # report progress
  if(right(j,3) == '000'){
    print(paste(j,'at',Sys.time()))
    flush.console()
  }
}

# Compute the sample means
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Mns <-aggregate(Smps[, 1], list(Smps$Drw), mean)

# Density plot of means
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
d <- density(Mns$x)
plot(d,xlab = 'Means', las=1, main = '')
polygon(d, col="blue", border="blue")

我希望有一个具有这种分层采样功能的R包,但我正在努力寻找以我能理解的方式工作的R包。输入一个带有分组字段和要从每个组中抽取的样本数量的数据帧的东西是我期望的东西,它已经被写成允许一个组的重复采样。任何指向工作的例子的指针都将不胜感激。理想情况下,我会准备从一个具有更多层数的已知人口中抽取100,000个分层样本,然后绘制均值的分布(但要快)

EN

回答 1

Stack Overflow用户

发布于 2020-05-19 08:27:07

离开这个问题一段时间后,我发现了一个名为'fifer‘(https://www.rdocumentation.org/packages/fifer/versions/1.1)的包,它似乎在包中包含一个分层函数,但不幸的是,这个包不能在最新版本的R上工作。然而,我确实从Ananda Mahto (https://gist.github.com/mrdwab/6424112)中找到了一个聪明的分层函数,它工作得很好,但代价是在脚本中有一个相当长的函数,而不是加载一个包的一行。我使用此函数解决上述问题的方法如下所示。

代码语言:javascript
复制
#Dummy population made up of dice throws - 18 per row
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
P1 <- as.data.frame(c(5,6,5,1,6,4,2,2,4,4,6,6,5,2,3,5,1,6))
P1$Zn <- 1
names(P1) <- c('Die','Zn')
Dt <- P1

P2 <- as.data.frame(c(2,5,4,5,5,5,3,3,2,5,6,1,2,5,4,3,6,1))
P2$Zn <- 2
names(P2) <- c('Die','Zn')
Dt <- rbind(Dt,P2)

#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
# Stratfed function from web
# https://gist.github.com/mrdwab/6424112
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

stratified <- function(df, group, size, select = NULL, 
                       replace = FALSE, bothSets = FALSE) {
  if (is.null(select)) {
    df <- df
  } else {
    if (is.null(names(select))) stop("'select' must be a named list")
    if (!all(names(select) %in% names(df)))
      stop("Please verify your 'select' argument")
    temp <- sapply(names(select),
                   function(x) df[[x]] %in% select[[x]])
    df <- df[rowSums(temp) == length(select), ]
  }
  df.interaction <- interaction(df[group], drop = TRUE)
  df.table <- table(df.interaction)
  df.split <- split(df, df.interaction)
  if (length(size) > 1) {
    if (length(size) != length(df.split))
      stop("Number of groups is ", length(df.split),
           " but number of sizes supplied is ", length(size))
    if (is.null(names(size))) {
      n <- setNames(size, names(df.split))
      message(sQuote("size"), " vector entered as:\n\nsize = structure(c(",
              paste(n, collapse = ", "), "),\n.Names = c(",
              paste(shQuote(names(n)), collapse = ", "), ")) \n\n")
    } else {
      ifelse(all(names(size) %in% names(df.split)),
             n <- size[names(df.split)],
             stop("Named vector supplied with names ",
                  paste(names(size), collapse = ", "),
                  "\n but the names for the group levels are ",
                  paste(names(df.split), collapse = ", ")))
    }
  } else if (size < 1) {
    n <- round(df.table * size, digits = 0)
  } else if (size >= 1) {
    if (all(df.table >= size) || isTRUE(replace)) {
      n <- setNames(rep(size, length.out = length(df.split)),
                    names(df.split))
    } else {
      message(
        "Some groups\n---",
        paste(names(df.table[df.table < size]), collapse = ", "),
        "---\ncontain fewer observations",
        " than desired number of samples.\n",
        "All observations have been returned from those groups.")
      n <- c(sapply(df.table[df.table >= size], function(x) x = size),
             df.table[df.table < size])
    }
  }
  temp <- lapply(
    names(df.split),
    function(x) df.split[[x]][sample(df.table[x],
                                     n[x], replace = replace), ])
  set1 <- do.call("rbind", temp)

  if (isTRUE(bothSets)) {
    set2 <- df[!rownames(df) %in% rownames(set1), ]
    list(SET1 = set1, SET2 = set2)
  } else {
    set1
  }
}


# Empty dataframe to hold random draws
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Smps <- data.frame(Die = numeric(), Zn = numeric())

# Right function for reporting progress
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
right = function(text, num_char) {
  substr(text, nchar(text) - (num_char-1), nchar(text))
}

# Draw stratifed samples one from each row
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
n <- 10000          # number of draws
for (j in 1:n){
    y <- stratified(Dt,"Zn",1)
    y <- cbind(y,j)
    Smps <- rbind(Smps,y)
  # report progress
  if(right(j,3) == '000'){
    print(paste(j,'at',Sys.time()))
    flush.console()
  }
}

# Compute the sample means
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Mns <-aggregate(Smps[, 1], list(Smps$j), mean)

# Density plot of means
#~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
d <- density(Mns$x)
plot(d,xlab = 'Means', las=1, main = '')
polygon(d, col="blue", border="blue")
票数 1
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页面原文内容由Stack Overflow提供。腾讯云小微IT领域专用引擎提供翻译支持
原文链接:

https://stackoverflow.com/questions/60739665

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