我正在尝试运行包含ltree函数和运算符的PostgreSQL原生查询。
定义如下:
@NamedNativeQuery(
name = "pathSegmentQuery",
query = "select ltree2text(okm_path) as okm_path, " +
" index(okm_path, text2ltree(:lastSegment)) + 2 <> nlevel(okm_path) as haschild, " +
" case " +
" when index(okm_path, text2ltree(:lastSegment)) + 1 <> nlevel(okm_path) " +
" then ltree2text(subpath(okm_path, index(okm_path, text2ltree(:lastSegment)) + 1, 1)) " +
" end as child " +
"from document " +
"where okm_path ~ :pathLike " +
"and " +
"index(okm_path, text2ltree(:path)) + 1 <> nlevel(okm_path) ",
resultSetMapping = "pathSegmentQueryRSMapping")调用方式如下:
public List<PathSegment> getPathChildren(String path, String lastSegment) {
Query query = entityManager.createNamedQuery("pathSegmentQuery");
String pathLike = "'*." + path + ".*'";
query.setParameter("path", path);
query.setParameter("pathLike", pathLike);
query.setParameter("lastSegment", lastSegment);
return query.getResultList();
}结果是error ERROR: operator does not exist: ltree ~ character varying。
当我尝试直接对数据库运行查询时,它运行正常:
select ltree2text(okm_path) as okm_path,
index(okm_path, text2ltree('_root_')) + 2 <> nlevel(okm_path) as haschild,
case
when index(okm_path, text2ltree('_root_')) + 1 <> nlevel(okm_path)
then ltree2text(subpath(okm_path, index(okm_path, text2ltree('_root_')) + 1, 1))
end as child
from document
where
okm_path ~ '*._root_.*'
and
index(okm_path, text2ltree('_root_')) + 1 <> nlevel(okm_path)从错误中可以明显看出hibernate(?)我不喜欢~操作符右侧的类型,但正如您所看到的,我在后面的查询中使用了该字符串,并且运行良好。
那么,我需要如何处理hibernate查询才能成功运行查询呢?
编辑:当我用"where okm_path ~ '*._root_.*' "替换okm_path ~ :pathLike时,我将得到:
org.postgresql.util.PSQLException: ERROR: syntax error at position 0错误
hibernate: 5.2.9
postgresql: 9.2.23
发布于 2018-12-28 05:27:54
事实证明,当您对lquery执行操作时,需要调用lquery()函数。
因此,我的查询转换为
...
where okm_path ~ lquery(:pathLike)
...这就解决了这个问题
发布于 2018-12-26 23:11:23
错误
operator does not exist: ltree ~ character varying应该理解为
operator does not exist: <left_data_type> <operator> <right_data_type> varying这意味着没有为这些数据类型定义运算符。例如,当运算符的左侧是整数而右侧是varchar时,就会发生这种情况,错误是ERROR: operator does not exist: integer = character varying。
这里的问题是,当您设置右侧的值时,
query.setParameter("pathLike", pathLike) pathLike是一个字符串。所以Postgres将其看作是将ltree与字符串进行比较。当您直接执行SQL时,右边是一个ltree表达式,而不是一个字符串。
我不确定这是否有效,但你能尝试一下ltree可以直接转换为varchar吗,但你能试试这个吗?:
query.setParameter("pathLike", pathLike, Hibernate.OBJECT)https://stackoverflow.com/questions/53933692
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