我想在我的数据框中转换成这样的格式df'Start Date‘2013-12-02,我想创建一个列,它根据开始日期告诉我星期几的名称。
def with_weekday(dataframe, date_field):
dataframe = dataframe.copy(deep=True)
dataframe ['Weekday'] = day_name(dataframe['Start Date']) #help here
return dataframe
#the 'Start Date' is the column with dates that I want to convert with this format2013-12-02发布于 2020-11-24 13:56:14
你可以这样做
df['day_name'] = pd.to_datetime(df['start_date']).dt.day_name()发布于 2020-11-24 13:47:29
对于日期名称,您可以编写一个简单的方法
def get_day_name(date):
day_name= ['Monday', 'Tuesday', 'Wednesday', 'Thursday', 'Friday', 'Saturday','Sunday']
day = datetime.datetime. strptime(date, '%d %m %Y'). weekday()
return day_name[day]
df['day_name'] = df['start_date'].apply(lambda x: get_day_name(x))https://stackoverflow.com/questions/64979585
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