在OpenGL4中旋转相机的问题

Question

我是一个通过glm库使用现代OpenGL的初学者，我试图创建带有相机移动的键盘移动(WSAD表示向前、向后、向右)和Q& E(顺时针和逆时针)。

当我尝试在Y轴上做一个完整的旋转时，它似乎做了半个旋转，然后跳回到起点(假设是一个180度的圆弧)。虽然旋转有问题，但前进方向也有问题，它会改变，而不是直线向前移动，当我们改变旋转时，向前移动被向左或向右偏移。

    glm::vec3 eyepos = glm::vec3(-0.6f, -0.4f, 31.1f);
    glm::vec3 frontvector = glm::vec3(0.0f, 0.0f, -1.0f);//looking         pointing vector
    glm::vec3 lookvector = glm::vec3(0.0f, 0.0f, -1.0f);
    glm::vec3 flatupvec = glm::vec3(0.0f, 1.0f, 0.0f);
    glm::vec3 upvec = glm::vec3(0.0f, 1.0f, 0.0f);

    glm::mat4 viewmatrix;
    glm::mat4 projectionmatrix;//camera lens, projection matrix, need an                 aspect ratio function here /3D FOV

    GLfloat movespeed = 0.1f;
    GLfloat turnspeed = 1.0f;

    //********************MOVEMENT_TRANSFORMS***********************************
        if (kb.w == true) { eyepos += frontvector *  movespeed;         }   //move up
        if (kb.s == true) { eyepos -= frontvector *  movespeed; }   //move down
        if (kb.q == true) { glm::quat q =         glm::angleAxis(glm::radians(turnspeed),
            glm::vec3(0, 1, 0)); frontvector = (frontvector * q);         }//turn left (yaw)
        if (kb.e == true) { glm::quat q =         glm::angleAxis(glm::radians(-turnspeed), 
            glm::vec3(0, 1, 0)); frontvector = (frontvector * q);         }//turn right (yaw)
        if (kb.a == true) { eyepos -=         glm::normalize(glm::cross(frontvector, flatupvec)) * movespeed; }         //strafe left
        if (kb.d == true) { eyepos +=         glm::normalize(glm::cross(frontvector, flatupvec)) * movespeed; }         //strafe right
        if (kb.r == true) { eyepos += flatupvec * movespeed; }  //move         up
        if (kb.f == true) { eyepos -= flatupvec * movespeed; }  //move         down
                //********************ROTATIONS_EYEPOINT************************************
        if (kb.t == true) { glm::quat q = glm::angleAxis(turnspeed,         glm::vec3(1, 0, 0)); lookvector = q * lookvector; } //pitch up
        if (kb.g == true) { glm::quat q = glm::angleAxis(-turnspeed,         glm::vec3(1, 0, 0)); lookvector = q * lookvector; }//pitch down
        if (kb.z == true) { glm::quat q = glm::angleAxis(-turnspeed,         glm::vec3(0, 0, 1)); upvec = q * upvec; }  //roll left
        if (kb.x == true) { glm::quat q = glm::angleAxis(turnspeed,         glm::vec3(0, 0, 1)); upvec = q * upvec; }   //roll right
        if (kb.c == true) { glm::quat q = glm::angleAxis(turnspeed,         glm::vec3(0, 1, 0)); lookvector = q * lookvector; } //yaw left
        if (kb.v == true) { glm::quat q = glm::angleAxis(-turnspeed,         glm::vec3(0, 1, 0)); lookvector = q * lookvector; }//yaw right

        viewmatrix = glm::lookAt( eyepos, eyepos + frontvector + lookvector, upvec);
        projectionmatrix = glm::perspective(45.0f, 1.8f, 0.0001f, 500.0f);

Answer 1

问题出在你的外貌矢量上。你的函数的工作原理是说你在(10,0,10)，你正在看((10,0,10)+(0,0，-1)+(0,0，-1))，它等于(10,0,8)或一直向前。所以假设你看起来向右((10,0,10)+(0.9,0，-0.1)+(0,0，-1))，等于(10.9,0,8.9)，那么一切都大致还不错。但是假设你把它几乎变成max ( (10,0,10) +(0.1,0,0.9)+(0,0，-1))，它等于(10.1,0,9.9)，比较(10.1,0,9.9)和(10,0,8)到(10,0,10)仍然是相同的向量(这可以解释180度圆弧)，(10,0,10)眼点和(10，0，10)看起来是模棱两可的，因此你的问题是"viewmatrix = glm:: lookat (眼点，眼点+正面向量+查找向量，upvec)；“调用并同时包含frontvector和lookvector，并且程序本身就是这样，您可能希望删除该调用的frontvector部分，但这是一段不错的代码;)