好了,我正在尝试编写一个矩形,其中包含多个连接在一起的三角形条带。根据:http://www.corehtml5.com/trianglestripfundamentals.php
当您有多行时,您需要处理环绕的三角形。然而,在我的代码示例中使用建议的算法,我得到了不正确的indice结果。
下面是我的示例,其中包含输出。
我尝试了复制/粘贴建议的算法,但它似乎没有返回正确的结果。
// Create the Index Points for the buffer array.
var rows=2;
var cols=3;
var grid = rows*cols;
var offset;
var pos = [];
var index = 0;
var mpOffset = 1;
for (var row = 0; row <= rows; ++row)
{
offsetY = row * (mpOffset / rows);
for (var col = 0; col <= cols; ++col)
{
offsetX = col * (mpOffset / cols);
pos[index+0] = (offsetX);
pos[index+1] = (offsetY);
index+=2;
}
}
log.info("pos="+JSON.stringify(pos)); // <-- Correct working good.
log.info("pos.length="+pos.length);
function initializeGrid(cols,rows)
{
var trianglestrip = [];
var RCvertices=2*cols*(rows-1);
var TSvertices=2*cols*(rows-1)+2*(rows-2);
var numVertices=TSvertices;
var j=0;
for(var i = 1; i <= RCvertices; i += 2)
{
trianglestrip[ j ] = (1 +i)/2;
trianglestrip[ j +1 ] = (cols*2 + i + 1) / 2;
if( trianglestrip[ j +1 ] % cols == 0)
{
if( trianglestrip[ j +1 ] != cols && trianglestrip[ j +1 ] != cols*rows )
{
trianglestrip[ j +2 ] = trianglestrip[ j +1 ];
trianglestrip[ j +3 ] = (1 + i + 2) / 2;
j += 2;
}
}
j += 2;
}
return trianglestrip;
}
var triStrip = initializeGrid(cols,rows);
log.info("triStrip="+JSON.stringify(triStrip)); // <-- Bad Not working.
log.info("triStrip.length="+triStrip.length);
// Generating the actual Point strip.
var actualStrip = [];
for (var i = 0 ; i < triStrip.length; ++i)
{
actualStrip.push(pos[(triStrip[i]-1)*2+0]);
actualStrip.push(pos[(triStrip[i]-1)*2+1]);
}
log.info("actualStrip="+JSON.stringify(actualStrip));
log.info("actualStrip.length="+actualStrip.length);指标应为: 1,5,2,6,3,7,4,8,8,5,5,9,6,10,7,11,8,12
发布于 2019-04-05 20:28:57
我最终重新创建了计算三角形条带指数的函数。还没有完全测试它,但它可以在网站上的示例中重新创建3x2网格。
代码如下:
// This calculates the triangle points in a rectangular triangle strip.
// Used for 3D Webgl texture mapping.
// Copyright Joshua Langley 2019.
var rows=2;
var cols=3;
var grid = rows*cols;
var offset;
var pos = [];
var index = 0;
var mpOffset = 1;
var offsetX, offsetY;
for (var row = 0; row <= rows; ++row)
{
offsetY = row * (mpOffset / rows);
for (var col = 0; col <= cols; ++col)
{
offsetX = col * (mpOffset / cols);
pos[index+0] = (offsetX);
pos[index+1] = (offsetY);
index+=2;
}
}
log.info("pos="+JSON.stringify(pos));
log.info("pos.length="+pos.length);
var rows=rows+1,cols=cols+1; // Important this counting Points not Squares.
var grid = rows*cols;
var offset;
var indices = [];
var indice = 0;
var offset;
var doublePoints = false;
var tPoint, bPoint;
for (var row = 0; row < rows; ++row)
{
for (var col = 0; col < (cols-1); ++col)
{
offset = row * rows + col;
tPoint = offset+1;
bPoint = offset+cols+1;
if (bPoint > grid)
continue;
indices.push(tPoint);
indices.push(bPoint);
if (offset > 0 && (bPoint+1) < grid && (offset+1) % cols == 0)
{
indices.push(bPoint);
indices.push(tPoint+1);
}
}
}
log.info("indices="+JSON.stringify(indices)); // Expected Result
log.info("indices.length="+indices.length);
var actualStrip = [];
for (var i = 0 ; i < indices.length; ++i)
{
actualStrip.push(pos[(indices[i]-1)*2+0]);
actualStrip.push(pos[(indices[i]-1)*2+1]);
}
log.info("actualStrip="+JSON.stringify(actualStrip));
log.info("actualStrip.length="+actualStrip.length);https://stackoverflow.com/questions/55529953
复制相似问题