Bash trap命令无法捕获致命的php脚本退出代码255

Question

问题的最小示例：

#!/bin/bash

errHandler() {
    echo "Something went wrong. Exiting now."
    exit 1
}
trap 'errHandler' ERR INT

pi_process () {
    bin/pi $@
    echo $?
}

pi_process stuff

bin/pi是一个php脚本，它正在退出，退出代码为255，并出现致命错误。然而，bash陷阱并没有被捕获。怎么会这样?

Answer 1

set -o functrace似乎没有做您所期望的事情。

试试这个：

#! /bin/bash

set -e

errHandler() {
    echo "Something went wrong. Exiting now."
    exit 1
}
trap 'errHandler' EXIT

pi_process () {
    false
    echo $?
}

pi_process stuff