如果发生未处理的错误,则http4s返回InternalServerError。当InternalServerError发生时,是否可以记录请求的url?如果是,最好的方法是什么?
发布于 2020-11-23 19:52:05
它不是开箱即用吗?
以下是来自快速入门指南https://http4s.org/v0.21/的g8模板项目的日志,其中添加了抛出运行时异常的路由:
[ioapp-compute-1] INFO o.h.s.m.Logger - HTTP/1.1 GET /bad_joke Headers(Accept: */*, Cache-Control: no-cache, Host: localhost:8089, Connection: Keep-Alive, User-Agent: Apache-HttpClient/4.5.12 (Java/11.0.8), Accept-Encoding: gzip,deflate) body=""
[ioapp-compute-1] INFO o.h.s.m.Logger - service raised an error: class java.lang.RuntimeException
[ioapp-compute-1] ERROR o.h.s.service-errors - Error servicing request: GET /bad_joke from 127.0.0.1
java.lang.RuntimeException: haha
at pack.H4sRoutes$$anonfun$jokeRoutes$1.applyOrElse(H4sRoutes.scala:19)
at pack.H4sRoutes$$anonfun$jokeRoutes$1.applyOrElse(H4sRoutes.scala:13)
at $anonfun$combineK$1 @ org.http4s.syntax.KleisliResponseOps.$anonfun$orNotFound$1(KleisliSyntax.scala:38)
at getOrElse @ org.http4s.syntax.KleisliResponseOps.$anonfun$orNotFound$1(KleisliSyntax.scala:38)
at guaranteeCase$extension @ org.http4s.server.middleware.RequestLogger$.$anonfun$impl$9(RequestLogger.scala:97)
at map @ org.http4s.server.middleware.RequestLogger$.$anonfun$impl$9(RequestLogger.scala:101)
at flatMap @ org.http4s.server.middleware.RequestLogger$.$anonfun$impl$7(RequestLogger.scala:82)
at flatMap @ org.http4s.server.middleware.ResponseLogger$.$anonfun$impl$7(ResponseLogger.scala:65)
at guaranteeCase$extension @ org.http4s.server.middleware.ResponseLogger$.$anonfun$impl$7(ResponseLogger.scala:88)
at main$ @ pack.Main$.main(Main.scala:5)https://stackoverflow.com/questions/64967413
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