在下面的this link示例中,我希望通过选择或更改汽车型号选项来将汽车型号设置为名称属性。目前,它给出的汽车名称作为第二个选择选项(carmodel)的值
var carsAndModels = {};
carsAndModels['VO'] = ['V70', 'XC60', 'XC90'];
carsAndModels['VW'] = ['Golf', 'Polo', 'Scirocco', 'Touareg'];
carsAndModels['BMW'] = ['M6', 'X5', 'Z3'];
function ChangeCarList() {
var carList = document.getElementById("car");
var modelList = document.getElementById("carmodel");
var selCar = carList.options[carList.selectedIndex].value;
while (modelList.options.length) {
modelList.remove(0);
}
var cars = carsAndModels[selCar];
if (cars) {
var i;
for (i = 0; i < cars.length; i++) {
var car = new Option(cars[i], i);
modelList.options.add(car);
}
}
}<select id="car" onchange="ChangeCarList()">
<option value="">-- Car --</option>
<option value="VO">Volvo</option>
<option value="VW">Volkswagen</option>
<option value="BMW">BMW</option>
</select>
<select id="carmodel"></select>
它插入带有名称的汽车型号的索引号,而不是汽车型号name.with var_dump($_POST['model']);其给定的string(1) "1"
发布于 2019-08-29 21:56:54
name不是option的有效属性,因此您无法添加它。不过,您也可以使用data-name:
car.dataset.name = cars[i];
var carsAndModels = {};
carsAndModels['VO'] = ['V70', 'XC60', 'XC90'];
carsAndModels['VW'] = ['Golf', 'Polo', 'Scirocco', 'Touareg'];
carsAndModels['BMW'] = ['M6', 'X5', 'Z3'];
function ChangeCarList() {
var carList = document.getElementById("car");
var modelList = document.getElementById("carmodel");
var selCar = carList.options[carList.selectedIndex].value;
while (modelList.options.length) {
modelList.remove(0);
}
var cars = carsAndModels[selCar];
if (cars) {
var i;
for (i = 0; i < cars.length; i++) {
var car = new Option(cars[i], i);
car.dataset.name = cars[i]; // <- add the data-name here
modelList.options.add(car);
}
}
}<select id="car" onchange="ChangeCarList()">
<option value="">-- Car --</option>
<option value="VO">Volvo</option>
<option value="VW">Volkswagen</option>
<option value="BMW">BMW</option>
</select>
<select id="carmodel"></select>
https://stackoverflow.com/questions/57711662
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